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Snowcat [4.5K]
3 years ago
7

The table below shows some input and output values for a function named F(n). Which of the following equations describes F(n)?

Mathematics
2 answers:
RSB [31]3 years ago
8 0
The equation in choice-'C' describes F(n).
Klio2033 [76]3 years ago
6 0
It looks like it would be C, but I'm not sure 
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Answer the question as soon as possible
expeople1 [14]

Answer:

  • D. Distributive

Step-by-step explanation:

<u>This is:</u>

  • a(b + c) = ab + ac  - Distributive property

Correct choice is D

6 0
3 years ago
A baseball card bought for $75 increases in value by 3% per year. what is the value of the card after 15 years
sammy [17]
If the value of the baseball card increases by 3% per year then we can say that each year the value of the card may be multiplied by 103% = 1.03, thus:

Value after n years = original price*(1.03)^n
Value after 15 years = 75*(1.03)^15
= $116.85
8 0
3 years ago
What is the value of 10P10
storchak [24]
ONO THAT NOT THE ANSWER THIS IS [3,628,800] 10P10=10, AND 0!= 10 TIMES 9 TIMES 8 TIMES 7 TIMES 6 TIMES 5 TIMES 4 TIMES 3 TIMES 2 TIMES 1= 3,628,800.
7 0
3 years ago
The function f(x) has a vertical asymptote at x = [BLANK].
kolezko [41]

Answer:

-1

Step-by-step explanation:

Based on the photo the asymptote will be x= - 1 because it is approaching it but never touching it

3 0
3 years ago
Findℒ{f(t)}by first using a trigonometric identity. (Write your answer as a function of s.)f(t) = 12 cost −π6
allsm [11]

Answer:

L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]

Step-by-step explanation:

Given that:

f(t)  = 12 cos (t- \dfrac{\pi}{6})

recall that:

cos (A-B) = cos AcosB + sin A sin B

∴

f(t) = 12 [cos\  t \  cos \dfrac{\pi}{6}+ sin \ t  \ sin \dfrac{\pi}{6}]

f(t) = 12 [cos \  t \ \dfrac{3}{2}+ sin  \ t  \ sin \dfrac{1}{2}]

f(t) = 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t)

L(f(t)) = L ( 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t) ]

L(f(t)) = 6 \sqrt{3} \ L [cos \ (t) ] + 6\ L [ sin \ (t) ]

L(f(t)) = 6 \sqrt{3}  \dfrac{S}{S^2 + 1^2}+ 6 \dfrac{1}{S^2 +1^2}

L(f(t)) = \dfrac{6 \sqrt{3} +6 }{S^2+1}

L(f(t)) = \dfrac{6( \sqrt{3} \ S +1 }{S^2+1}

L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]

7 0
3 years ago
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