Answer:
a) -4. -9. -2
-3. -5. -7
-8. -1. -6
b) -3. 4. -1
2 0 -2
1. -4 3
Step-by-step explanation:
a) -4. -9. -2
-3. -5. -7
-8. -1. -6
b) -3. 4. -1
2 0 -2
1. -4 3
Answer:
False, False, A. 180
Step-by-step explanation:
A flat line is 180 degrees. A right isosceles triangle has one right angle. None of the sides on a scalene triangle are the same.
Answer:
He has 45 kids now.
Step-by-step explanation:
Answer:
The answer is 100 in
Step-by-step explanation:
The pythagorean theorm states that, for any right triangle where a and b are the legs and c is the hypotenuse, a^2 + b^2 = c^2. So, we can substitute and solve.
18^2 + 26^ 2 = c^2
324 + 676 = c^2
1000=c^2
Square root of 1000 = c
100.0=c
Hope this helps!
The point from a given height to the horizon form a line that is tangent to the curvature of the earth.
The angle of the sector from observation height to horizon point is:
cosa=r/(r+h), where h is the height above the surface of the earth and r is the radius of the earth...
a=arccost(r/(r+h))
And the arc length is just 2pra/360=pra/180
So the distance to the horizon along the curvature of the earth is:
(pr/180)arcos(r/(r+h))
And we have two of these arcs one from the periscope height to the horizon and one from the top of the ship to the horizon.
If we simplify the radius of the earth 3959mi you get
For the periscope:
(3959p/180)arcos(3959/(3959+h)) remember that 5 ft is 5/5280 mi
2.74 mi (to nearest hundredth of a mile)
And for the top of the ship:
3959p/180)arcos(3959/(3959+h)) where h is 50/5280
8.68 mi (to nearest hundredth of a mile)
So the total distance along the curvature of the earth between when the periscope can just see the top of the ship is:
2.74+8.68=11.42 miles