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vodka [1.7K]
3 years ago
9

PLEASE HELP!!!!!!!!!!!

Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

6in²

Step-by-step explanation:

the problem says the two triangular prisms are congruent.

the first triangle's volume is 90in³ and the height of the second triangular prism is 15. we use the formula fro the volume of the shape:

V=B * h

we substitute the values we know:

90in³=B*15

90/15 = B

6in²= B

So the area of the base is 6in²

Hope this helps :)

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Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?
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Answer:

Step-by-step explanation:

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\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\

(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+  \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.

8 0
1 year ago
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belka [17]

Answer:

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hope this helps ^-^ have a wonderful day

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