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Alexxx [7]
3 years ago
8

Shannon wants to work with renewable energy. She is researching what it would take to become a geochemist. A geochemist is someo

ne who uses chemistry to study water and elements in it. What skill or ability well Shannon need to be the most effective in this position?
Computers and Technology
1 answer:
Liula [17]3 years ago
3 0

Answer:

Critical thinking

Explanation:

Shannon needs to be a Critical thinker to be effective in this position. Critical thinking has to do with giving deep and good thoughts while doing analysis, or assessment in other to come up with good judgements about a subject or topic.

Since she is going to be studying water and elements in it, she would be doing a lot of analysis and assessments and In other to do good in her field she must learn to think critically before arriving at her conclusions.

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Lyrx [107]
The points are a leveling up system. You also use the points when you ask questions as well. Hope this helps! :-)
5 0
3 years ago
The program is to be answered in Java Programming not C++ Please answer the following: Modify the BarChart program to accept the
Solnce55 [7]

Answer:

import java.util.Scanner;

public class BarChart {

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);

//take input from user

System.out.println("Enter Score");

int score=sc.nextInt();

int count=score/10;

int i=1;

//print horizontal bar

//if you want to print vertical bar then simply change into print which is replace by println

while(i<=count)

{

System.out.print("*");

i++;

}

}

}

Explanation:

6 0
3 years ago
HP laptop computers are produced on a line, with multiple workers completing one or two specific tasks to assemble the laptop. T
EastWind [94]

Answer:

HP laptop computers are produced on a line, with multiple workers completing one or two specific tasks to assemble the laptop. This is an example of <u>job Specialization Negatives </u>which can leave to boredom and dissatisfaction. A solution may be to introduce <u>job rotation  </u>where employees shift from one job to another.

Explanation:

One of the major disadvantages of specialization in a job is the repetitive routine which leads to boredom. As the brain does not get actively involved in the same boring routines, so there is more number of chances of mistakes to be made. The employees may also feel not connected to the procedures as they work in just one area.

To avoid these circumstances, the managers of a company should initiate the idea of job rotations. Job rotation simply means shifting the job of an employee for a few days so that he/she can get a better understanding of the job and company.

5 0
3 years ago
C++
nikitadnepr [17]

Answer:

Check the explanation

Explanation:

<u>The Code</u>

#include <fstream>

#include <iostream>

#include <cmath>

#include <cstring>

#include <cstdlib>

#include <ctime>

using namespace std;

//Function Declarations

void fillArrayWithRandNos(int nos[],int size);

void displayArray(int nos[],int size);

double mean(int nos[],int size);

double variance(int nos[],int size);

double median(int nos[],int size);

int mode(int nos[],int size);

void histogram(int nos[],int size);

int main() {

  //Declaring variables

const int size=100;

srand(time(NULL));

 

// Creating array dynamically

int* nos = new int[size];

 

//Calling the functions

fillArrayWithRandNos(nos,size);

displayArray(nos,size);

cout<<"Mean :"<<mean(nos,size)<<endl;

cout<<"variance :"<<variance(nos,size)<<endl;

cout<<"Median :"<<median(nos,size)<<endl;

cout<<"Mode :"<<mode(nos,size)<<endl;

histogram(nos,size);

 

  return 0;

}

void fillArrayWithRandNos(int nos[],int size)

{

  for(int i=0;i<size;i++)

  {

      nos[i]=rand()%(45) + 55;

  }

}

void displayArray(int nos[],int size)

{

  cout<<"Displaying the array elements :"<<endl;

  for(int i=0;i<size;i++)

  {

      cout<<nos[i]<<" ";

      if((i+1)%10==0)

      cout<<endl;

  }

}

double mean(int nos[],int size)

{

  double sum=0;

  for(int i=0;i<size;i++)

  {

      sum+=nos[i];

  }

  return sum/size;

}

double variance(int nos[],int size)

{

  double avg=mean(nos,size);

 

double variance,sum=0;

for(int i=0;i<size;i++)

{

sum+=pow(nos[i]-avg,2);

}

//calculating the standard deviation of nos[] array

variance=(double)sum/(size);

return variance;

}

double median(int nos[],int size)

{

      //This Logic will Sort the Array of elements in Ascending order

  int temp;

  for (int i = 0; i < size; i++)

{

for (int j = i + 1; j < size; j++)

{

if (nos[i] > nos[j])

{

temp = nos[i];

nos[i] = nos[j];

nos[j] = temp;

}

}

}

 

int middle;

float med;

middle = (size / 2.0);

if (size % 2 == 0)

med = ((nos[middle - 1]) + (nos[middle])) / 2.0;

else

med = (nos[middle]);

return med;

}

int mode(int nos[],int size)

{

  int counter1 = 0, counter2, modevalue;

for (int i = 0; i < size; i++) {

counter2 = 0;

for (int j = i; j < size; j++) {

if (nos[i] == nos[j]) {

counter2++;

}

if (counter2 > counter1) {

counter1 = counter2;

modevalue = nos[i];

}

}

}

if (counter1 > 1)

return modevalue;

else

return 0;

}

void histogram(int nos[],int size)

{

  int hist[9]={0};

  for(int i=0;i<size;i++)

  {

      if(nos[i]>=55 && nos[i]<=59)

      {

      hist[0]++;

      }

      else if(nos[i]>=60 && nos[i]<=64)

      {

      hist[1]++;

      }

      else if(nos[i]>=65 && nos[i]<=69)

      {

      hist[2]++;

      }

      else if(nos[i]>=70 && nos[i]<=74)

      {

      hist[3]++;

      }

      else if(nos[i]>=75 && nos[i]<=79)

      {

      hist[4]++;

      }

      else if(nos[i]>=80 && nos[i]<=84)

      {

      hist[5]++;

      }

      else if(nos[i]>=85 && nos[i]<=89)

      {

      hist[6]++;

      }

      else if(nos[i]>=90 && nos[i]<=94)

      {

      hist[7]++;

      }

      else if(nos[i]>=95 && nos[i]<=99)

      {

      hist[8]++;

      }

  }

     

  cout<<"Displaying the count of numbers in each interval:"<<endl;

 

      int cnt=0;

  for(int i=55;i<=99;i+=5)

  {

  cout<<i<<"-"<<i+4<<"|"<<hist[cnt]<<endl;

 

      cnt++;

  }

 

  cout<<"Displaying the histogram :"<<endl;

  cnt=0;

  for(int i=55;i<=99;i+=5)

  {

  cout<<i<<"-"<<i+4<<"|";

  for(int j=0;j<hist[cnt];j++)

  {

      cout<<"*";

  }  

      cout<<endl;

      cnt++;

  }          

     

 

 

}

#########

___________________________

The output can be seen in the attached image below.

8 0
3 years ago
The function takes two string parameters; the first is the name of a file and the second is text. Complete the function to appen
castortr0y [4]

Answer:

The code for the function is given below in Python language

Explanation:

def append_string_to_file(filename, text):// function takes the filename // and text  to append

f = open(filename, 'a')

f.write(text) //function part that writes the text

f.close() //closing the file using the explicit close function

3 0
4 years ago
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