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3 years ago

10

Each of 7 samples has a different standard deviation. How many of the 7

1 answer:

elixir [45]3 years ago

7 0

Answer:

Step-by-step explanation:

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Given the endpoint (-9,3) and (1,8) partition the segment into the ratio 2:3<br>

Sindrei [870]

Answer:

$P = (-5,5)$

Step-by-step explanation:

Let the segments be A and B

$A = (-9,3)$

$B = (1,8)$

$m:n = 2:3$

Required

Determine the endpoints after it is divided into ratios.

<em>Let the point be represented with P</em>

The formula to use is:

$P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

Where

$A = (-9,3)$ ----- $(x_1,y_1)$

$B = (1,8)$ ------ $(x_2,y_2)$

So:

$P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

$P = (\frac{2 * 1 + 3 * -9}{2 + 3},\frac{2 * 8 + 3 * 3}{2 + 3})$

$P = (\frac{-25}{5},\frac{25}{5})$

$P = (-5,5)$

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2 years ago

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adelina 88 [10]

Answer:

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3 years ago

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3 years ago

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Lubov Fominskaja [6]

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2 years ago

Integrate G(x,y,z)equalsz over the parabolic cylinder yequalszsquared, 0less than or equalsxless than or equals2, 0less than

yKpoI14uk [10]

I gather you're supposed to compute the integral of $G(x,y,z)=z$ over a surface $S$ that is the part of the parabolic cylinder $y=z^2$ with $0\le x\le2$ and $0\le z\le\frac{\sqrt{15}}2$ .

We can parameterize $S$ by

$\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k$

with the given constraints on $x$ and $z$ . Take the normal vector to $S$ to be

$\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k$

so that the surface element is

$\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz$

Then in the integral, we have

$\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}$

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3 years ago