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telo118 [61]
3 years ago
9

Between what two consecutive integers is the square root of 29

Mathematics
2 answers:
lina2011 [118]3 years ago
3 0

Answer: 5 and 6

Step-by-step explanation:

sqrt1=1

sqrt4=2

sqrt9=3

sqrt16=4

sqrt25=5

sqrt29~5.4

sqrt36=6

IrinaVladis [17]3 years ago
3 0

Answer:

5 and 6

Step-by-step explanation:

The two integers be 'x' and 'y'. Since 'x' is an integer less than 5.38, it has to be 5.

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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
Which angle is vertical to BEC?
Lostsunrise [7]

Answer:

<AED

Step-by-step explanation:

Ima be real I cant really explain but i think that's right

3 0
3 years ago
BRAINLY AND 20 PTS TO WHOEVER GETS IT RIGHT
Makovka662 [10]

Answer:

D

Step-by-step explanation:

5 0
2 years ago
De cite ori trebuie micsorat numarul 1000 pentru a obtine numarul cu 10 mai putin decit 50.
amid [387]
The answer is 19.8 to ur problem

5 0
3 years ago
Amber has some state quarters in her pocket. She collects the following data by randomly pulling one quarter recordings the stat
ch4aika [34]
To do this problem, we need one more piece of information. He need to know the percent of the quarters that are from New York.

If you had that number, just multiply it by 300.

For example, if 10% of the coins were from New York, just multiply by 0.1.
0.1 x 300 = 30
4 0
3 years ago
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