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telo118 [61]
3 years ago
9

Between what two consecutive integers is the square root of 29

Mathematics
2 answers:
lina2011 [118]3 years ago
3 0

Answer: 5 and 6

Step-by-step explanation:

sqrt1=1

sqrt4=2

sqrt9=3

sqrt16=4

sqrt25=5

sqrt29~5.4

sqrt36=6

IrinaVladis [17]3 years ago
3 0

Answer:

5 and 6

Step-by-step explanation:

The two integers be 'x' and 'y'. Since 'x' is an integer less than 5.38, it has to be 5.

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Solve for x in the triangle. Round your answer to the nearest tenth.
kramer

Answer:

<h2>x = 10.3</h2>

Step-by-step explanation:

Use sine.

sine=\dfrac{opposite}{hypotenuse}

We have:

opposite=x\\hypotenuse=16

\sin40^o\approx0.6428        <em>look at the table in the picture</em>

Substitute:

\dfrac{x}{16}=0.6428         <em>multiply both sides by 16</em>

x=10.2848\to x\approx10.3

5 0
3 years ago
What is the domain of F(x) = 1/x ?
Elenna [48]

Step-by-step explanation:

The domain is the possible x values of a function.

Since our function is a reciprocal function, our denominator can't equal 0. Note x=0, is a vertical asymptote.

So our domain is

All Reals except 0,

or (-oo,0) U (0, oo).

6 0
2 years ago
Compare adding unlike fractions and adding like fractions
muminat

Answer:

We just add numerators and rewrite denominator.

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

Step-by-step explanation:

You mean unlike denominators and like denominators.

Adding like dominators: We just add numerators and rewrite denominator :

Example : \frac{1}{4} +\frac{2}{4}=\frac{1+2}{4}  =\frac{3}{4}

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

For example :

\frac{1}{5}+\frac{3}{4}

LCM for 5 and 4 is 20 : Now, divide by 5 and multiply by 1 for first fraction. 20 divide by 4 and multiply by 3 :

\frac{1*4}{20} +\frac{3*5}{20}=\frac{4}{20} +\frac{15}{20}=\frac{19}{20}

4 0
3 years ago
Read 2 more answers
Solve the problem by multiplying first. A clothing store is having a sale on shirts and jeans. Four shirts and two pairs of jean
ella [17]

We will solve this by suing simultaneous equations,

⇒ 5s + 3j = 87

    4s + 2j = 64

Multiply the first equation with 4 and the second one with 5, this is to get one of the values equal so that we can cancel them out,

⇒ (5s + 3j = 87) × 4

    (4s + 2j = 64) × 5

∴ ⇒ 20s + 12j = 348

       20s + 10j = 320

Subtract both the equations. This is how your result (after subtraction) should look like,

  ⇒ 2j = 28

∴ ⇒ j = $14

Now replace the value of 'j' in one of the original equations,

⇒ 4s + 2(14) = 64

⇒ 4s + 28 = 64

⇒ 4s = 64 - 28

⇒ 4s = 36

∴ ⇒ s = $9

Therefore, one pair of jeans cost $14 and a shirt costs $9

Hope you understood! Feel free to ask me if you didn't understand a step.

5 0
3 years ago
Three kids play tennis at the same tennis courts. Mark plays every fourth day, David plays every seventh day and Bryan plays eve
jonny [76]

Answer:

Wednesday (9 weeks later) = 10th October.

Step-by-step explanation:

We label the days with the initials of the names.

M= 4

D = 7

B = 6

LCM of 6 +7 = 42

LCM of 6+7 + 4 = 84

We find 84 is the amount of days we need to add on to july 18th

We first find the weeks 84/7 = 9 weeks.

As Wednesday July 18th is exclusive it would be 84 days after this event.

18+ 84 = 102 days.

31 days in july = 31

31 days in Aug = 31

30 days in Sept = 30

= 92

102-92 = 10

We now know date is Wednesday 10th October

We can check 84 days = 9 weeks

13 days in July makes 31st july

31 days in Aug makes 31st Aug

30 days in Sept makes 30th Sept

= 74 days + 10 days = 84

10th October is the checked date and we know it is also a Wednesday as Wednesday had stayed exclusive and prove that there are 7 days in the week to account x 9, to account for an exact 9 weeks later duration.

6 0
4 years ago
Read 2 more answers
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