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Kay [80]
3 years ago
10

Assume that you have paired values consisting of heights​ (in inches) and weights​ (in lb) from 40 randomly selected men. The li

near correlation coefficient r is 0.5130.513. Find the value of the coefficient of determination. What practical information does the coefficient of determination​ provide?
Mathematics
1 answer:
Over [174]3 years ago
3 0

Answer:

The value of the coefficient of determination is 0.263 or 26.3%.

Step-by-step explanation:

<em>R</em>-squared is a statistical quantity that measures, just how near the values are to the fitted regression line. It is also known as the coefficient of determination.

A high R² value or an R² value approaching 1.0 would indicate a high degree of explanatory power.

The R-squared value is usually taken as “the percentage of dissimilarity in one variable explained by the other variable,” or “the percentage of dissimilarity shared between the two variables.”

The R² value is the square of the correlation coefficient.

The correlation coefficient between heights​ (in inches) and weights​ (in lb) of 40 randomly selected men is:

<em>r</em> = 0.513.

Compute the value of the coefficient of determination as follows:

R^{2}=(r)^{2}\\=(0.513)^{2}\\=0.263169\\\approx0.263

Thus, the value of the coefficient of determination is 0.263 or 26.3%.

This implies that the percentage of variation in the variable height explained by the variable weight is 26.3%.

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ddd [48]

Answer:

69.08

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In the United States, 35% of households own a 4K television. Suppose we take a random sample of 150 households. (a) Describe the
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Answer:

(a) The distribution of the sample proportion is Normal distribution.

(b) The probability that in this sample of 150 households that more than 50% own a 4K television is 0.00012.

Step-by-step explanation:

We are given that in the United States, 35% of households own a 4K television.

Suppose we take a random sample of 150 households.

<em>Let </em>\hat p<em> = sample proportion of households who own a 4K television.</em>

The z-score probability distribution for sample proportion is given by;

           Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

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     n = sample of households = 150

(a) The distribution of the sample proportion is related to the Normal distribution.

(b) Probability that in this sample of 150 households more than 50% own a 4K television is given by = P( \hat p > 0.50)

    P( \hat p > 0.50) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{ 0.50-0.35}{\sqrt{\frac{0.50(1-0.50)}{150} } } ) = P(Z > 3.67) = 1 - P(Z \leq 3.67)

                                                                   = 1 - 0.99988 = 0.00012

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 3.67 in the z table which has an area of 0.99988.</em>

Therefore, probability that in this sample of 150 households more than 50% own a 4K television is 0.00012.

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Read more about coordinate planes at:

brainly.com/question/7243416

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