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Kay [80]
3 years ago
10

Assume that you have paired values consisting of heights​ (in inches) and weights​ (in lb) from 40 randomly selected men. The li

near correlation coefficient r is 0.5130.513. Find the value of the coefficient of determination. What practical information does the coefficient of determination​ provide?
Mathematics
1 answer:
Over [174]3 years ago
3 0

Answer:

The value of the coefficient of determination is 0.263 or 26.3%.

Step-by-step explanation:

<em>R</em>-squared is a statistical quantity that measures, just how near the values are to the fitted regression line. It is also known as the coefficient of determination.

A high R² value or an R² value approaching 1.0 would indicate a high degree of explanatory power.

The R-squared value is usually taken as “the percentage of dissimilarity in one variable explained by the other variable,” or “the percentage of dissimilarity shared between the two variables.”

The R² value is the square of the correlation coefficient.

The correlation coefficient between heights​ (in inches) and weights​ (in lb) of 40 randomly selected men is:

<em>r</em> = 0.513.

Compute the value of the coefficient of determination as follows:

R^{2}=(r)^{2}\\=(0.513)^{2}\\=0.263169\\\approx0.263

Thus, the value of the coefficient of determination is 0.263 or 26.3%.

This implies that the percentage of variation in the variable height explained by the variable weight is 26.3%.

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In a call center that stays open all the time, calls arrive as a poisson process with a mean rate of 0.3 complaints per hour.(a)
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Data;

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  • x = 50
  • standard deviation = ?

<h3>Poission Rule</h3>

Using poission formula,

P(x=x) = \frac{e^-^\lambda - \lambda^x}{x!}\\\lambda = 0.3 per minute

Let's substitute the values into the formula.

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The probability the next call arrives after 2 hours.

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for 50 days;

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The standard deviation is given as

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Learn more on poission formula here;

brainly.com/question/7879375

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