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earnstyle [38]
3 years ago
13

What is the slope of the line?

Mathematics
1 answer:
Allisa [31]3 years ago
3 0

Answer:

<u>-1</u>

2

Step-by-step explanation:

(0,2) and (1,0) are the points on the line

Let (0,2) be (x1,y1) and (1,0) be (x2,y2)

slope(m)= <u>y2-y1</u>

x2-x1

=<u>1-0</u>

0-2

=<u>1</u>

-2

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Eight parentheses x plus two parentheses
jarptica [38.1K]

Answer:

10

Step-by-step explanation:

8+2=10

3 0
3 years ago
Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all
Norma-Jean [14]

Answer:

1 is Answer.

Step-by-step explanation

\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\

= \frac{(-1)*(omega + 1)}{omega^{2}  }

As we know that ω²+ω+1=0

Thus putting in above equation, we get

= \frac{1}{(-1)*omega } + \frac{1}{(-1)*omega^{2}  }

Rearranging and simplifying:

= \frac{-1}{omega } + \frac{-1}{omega^{2}  }

= \frac{(-1)*(omega + 1)}{omega^{2}  }

= \frac{(-1)*(- omega^{2} )}{omega^{2}  }

= 1 Answer

8 0
3 years ago
If sin F = 3/5 , what is cos G ?
alukav5142 [94]

Answer:

D

Step-by-step explanation:

side HG is 3

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sin F = 3/5 = opposite/hypotenuse

cos G is adjacent/hypotenuse

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3 0
3 years ago
Tanikwa started a new exercise program using the indoor track. In her first workout she ran 8 laps for every 4 laps that she wal
Elina [12.6K]

Answer:

The correct answer would be 2:1

Step-by-step explanation:

In order to find this, start with the ratio as it is written and sub in the values. Then simplify to the lowest possible terms.

Ran:Walker

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6 0
3 years ago
Geometry help! Please prove the following is a square with full explanation, I'm really lost.
Hoochie [10]

We have to show that this is a square, meaning all the sides are perpendicular and the same distance.  

A(3,4), B(2,-2), C(-4,-1), D(-3,5)

For each side we calculate the squared distance and the slope.  We don't have to bother to take the square root.  We'll subtract the points first because that difference, called the direction vector, goes into both the calculation of the slope and of the distance.

AB=B-A=(2 - 3, -2 - 4) = (-1, -6).   slope=-6/-1=6  AB²=(-1)²+(-6)²=37

BC=C-B=(-6, 1).  slope=1/-6=-1/6.   BC²=(-6)²+1²

CD=D-C=(1, 6).   slope=6/1=6    CD²=1²+6²=37

DA=A-D=(6,-1)   slope=-1/6     DA²=37

We see the negative reciprocal slopes, alternating between 6 and -1/6, indicating perpendicular sides.  We see they all have squared distance 37.  Equal perpendicular sides proves its a square.

If we do these problems enough we learn:  There's no point taking the square root.  In fact, there's really no point computing the slopes and the squared distances; we can see it's a square from the pattern of the direction vectors of the sides:  (-1, -6) (-6, 1) (1, 6) (6,-1)

5 0
4 years ago
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