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ycow [4]
3 years ago
11

Tx^2+3x-7=0 has two real solutions . what can b deduced about value of t ?​

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

The number of solutions of a quadratic equation

ax^2+bx+c=0

Depends on its discriminant

\Delta = b^2-4ac

  • If \Delta>0 there are two distinct solutions
  • If \Delta=0 there are two coincident solutions
  • If \Delta there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

b^2-4ac = 9+28t > 0 \iff t>-\dfrac{9}{28}

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