Question

What is a, b, and c in this quadratic equation?

Answer 1

Answer:

a = 8, b = −19, c = −89

Step-by-step explanation:

The quadratic equation:

$ax^2+bx+c=0$

We have:

$8x^2-19x=89$         subtract 89 from both sides

$8x^2-19x-89=0$

$8x^2+(-19)x+(-89)=0$

Therefore:

$a=8\\b=-19\\c=-89$