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3 years ago

Graph the solution set of the inequality. -4n +1 > -23

Mathematics

1 answer:

Natali [406]3 years ago

6 0

Answer:

honestly i dont know

Step-by-step explanation:

sorry about that

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I don't understand this question please help

Furkat [3]

Answer:

LM = 22

Step-by-step explanation:

11(44) = (LM)^2

484 = (LM)^2

LM = √484 = 22

8 0

2 years ago

Read 2 more answers

Give the domain and range.

Scrat [10]

Answer:

The domain: {-3, 0, 3}

The range: {-6, 0, 6}

Therefore, option (a) is correct.

Step-by-step explanation:

Given the table

x -3 0 3

y -6 0 6

Determining the Domain:

We know that the domain of a relation is the set of all the x-values of the set X.

In other words, the domain of relation consists of all the input values.

Therefore, the domain: {-3, 0, 3}

Determining the Range:

We know that the range of a relation is the set of all the y-values of the set Y.

In other words, the range of relation includes all the output values.

Therefore, the range: {-6, 0, 6}

Therefore, we conclude that option (a) is correct.

8 0

3 years ago

How do i solve this problem?<br> Y=100+50x

gogolik [260]

Answer:

Step-by-step explanation:

to solve this you would subtract 100 from each side :

Y = 100+50x

-100 -100

-100= 50x

then you would divide each side by 50 to get 'x'

-100/50=50x/50

-2 = x

7 0

4 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

kodGreya [7K]

In this questions, there are a few functions with more/less than and equal to symbol.
1. Answer: f(x)= 3
f(x)= 2<x ≤3
The x is [more than 2] and [less than 3] or [equal to 3]. The number that will fulfill the condition would be only 3 since 3 is [more than 2] and [equal to 3].

2. f(x)= 1
f(x)= 0<x ≤1
The x is [more than 0] and [less than 1] or [equal to 1]. The number that will fulfill the condition would be only 1 since 1 is [more than 0] and [equal to 1].

3. f(x)= x
f(x)= 1≤x ≤2
The x is [more than 1] or [equal to 1] and [less than 2] or [equal to 2]. The number that will fulfill the condition would be
1, since 1 is [equal to 1] and [less than 2]
2, since 2 is [more than 1] and [equal to 2]
The graph that follow the value would be: f(x)= x

4. Answer: f(x)= 4
f(x)= 3<x ≤4
The x is [more than 3] and [less than 4] or [equal to 4]. The number that will fulfill the condition would be only 4 since 4 is [more than 3] and [equal to 4].

7 0

3 years ago

Read 2 more answers

If A(−1, 1), B(−4, 5), C(−9, 5), and D(−6, 1) are the vertices of a quadrilateral, do the points form a rhombus? Justify your an

Flura [38]

Answer:

Yes, it is a rhombus because the slope of diagonal segment BD equals 2, the slope of diagonal segment AC equals -1/2, and the diagonals bisect each other.

Step-by-step explanation:

The slope of diagonal BD is ...

slope BD = (change in y)/(change in x) = (-4/-2) = 2

The slope of diagonal AC is ...

slope AC = (change in y)/(change in x) = (4/-8) = -1/2

The midpoint of BD is ...

((-4, 5) +(-6, 1))/2 = (-10, 6)/2 = (-5, 3)

The midpoint of AC is ...

((-1, 1) +(-9, 5))/2 = (-10, 6)/2 = (-5, 3)

so the diagonals bisect each other.

While the third statement is true (both midpoints are the same), that fact alone is not sufficient to allow the figure to be declared a rhombus. The diagonals must also be perpendicular (have slopes whose product is -1). The appropriate answer choice is the <em>second one</em>:

Yes, it is a rhombus because the slope of diagonal segment BD equals 2, the slope of diagonal segment AC equals -1/2, and the diagonals bisect each other.

3 0

3 years ago