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vlada-n [284]
3 years ago
6

Determine whether each function is continuous at x=5. Justify your answer using the continuity test.

Mathematics
1 answer:
irakobra [83]3 years ago
6 0

Answer:

2. f(x)=\frac{x^2}{x+5}

Step-by-step explanation:

When you replace x=5 into those functions you obtain:

1. f(x)=\sqrt{x^2-36} = \sqrt{5^2-36} = \sqrt{-11} \\2. f(x)=\frac{x^2}{x+5}=\frac{5^2}{5+5}=\frac{25}{10}

We can see that the function number 1, when the x=5 is replaced, falls into the imaginary numbers or complex domain, so the function is not continuous in the real domain.

On the other hand, the second function falls into the real domain whe x=5 is replaced, so the function is continuous in the real domain!

I hope you understand!

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Yuliya22 [10]
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4 0
2 years ago
On a coordinate plane, a shape is plotted with vertices of (3, 1), (0, 4), (3, 7), and (6, 4). what is the area of the shape if
QveST [7]
Let
<span>A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)

step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm

step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm

step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm

step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm

step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD

step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and 
AB and AD are perpendicular 
BC and CD are perpendicular

therefore
the shape is a square wit length side √18 cm

area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²

the answer is
18 cm²

see the attached figure


6 0
3 years ago
Hi! Could you help me me out and solve these two problems? "eight less than the product of seven and xxx", and "the sum of six a
Ann [662]

Given:

The given statement are:

a. Eight less than the product of seven and x.

b. The sum of six and the product of three and d.

To find:

The expression for the given statements.

Solution:

a.

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Eight less than the product of seven and x is 7x - 8.

Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.

b.

Product of 3 and d is 3×d = 3d.

The sum of six and the product of three and d is 6+3d.

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3 0
2 years ago
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elena-s [515]

Answer:

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5 0
2 years ago
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oksian1 [2.3K]

The correct answer is the second from the top.

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3 years ago
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