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3 years ago

Let x be a number. The sum of thirteen and twice a number

Mathematics

1 answer:

Kruka [31]3 years ago

3 0

Answer:

Step-by-step explanation:

Easy:

if x is the variable:

13+2x

2x+13

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5 quarts =how many fluid ounces

pishuonlain [190]

160 fluid ounces :) hope this helped

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3 years ago

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please help me. how would you change x + 3y = 18 -3x -12y = -75 to eliminate y showing all of the work

Svetlanka [38]

Answer:

x = -3

y = 7

Step-by-step explanation:

x + 3y = 18

-3x - 12y = -75

multiply first equation by 4

4 × (x + 3y) = 18 ➡ 4x + 12y = 72

now add the two equations up

4x + 12y - 3x -12y = 72 - 75 (-12y will eliminate 12y)

x = -3

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Mateus recorded the number of miles driven and the amount

IrinaK [193]

The maximum amount of miles that can be driven is A) 220 miles.

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3 years ago

What’s the answer help please !

vodka [1.7K]

Answer:

adjacent

Step-by-step explanation:

they are next to and adjoining eachother

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3 years ago

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I need help understanding this ASAP plz, I have a quiz over this next week!!!!

scZoUnD [109]

Answer:

Step-by-step explanation:

With any two points, you can find the line between them with:

$y = mx + b\\where\\m = \frac{y_2-y_1}{x_2-x_1}$

#1:

(-1, 1) -> (1, 3) $m = \frac{3-1}{1-(-1)} = 1, 3 = 1(1) + b, b = 2, y = x + 2$

(3, 4) -> (0, 2) $m = \frac{4-2}{3-0} = \frac{2}{3}, 2 = \frac{2}{3}(0) + b, y = \frac{2}{3}(x)+2$

(0, 1) -> (3, 3) $m = \frac{3-1}{3-0} = \frac{2}{3}, 1 = 2/3(0) + b, y = \frac{2}{3}(x) + 1$

Lines b and c are parallel because they have the same slopes

#2 is a bit easier

a: 2y = x + 12, $y = \frac{1}{2}(x) + 6$

b:2y - x = 5, $y = \frac{1}{2}(x) + \frac{5}{2}$

c: 2y + x = 4, $y = \frac{-1}{2}(x) + 2$

Since lines a and b have the same slope, they are parallel

#3:

(1, 3), y = 2x - 5

We have to find a line with a slope of 2 that passes through the two points

$y = 2x + b\\3 = 2(1) + b\\b = 1\\\\y = 2x + 1$

#4:

(-2, 1) , y = -4x + 3

We have to find a line with a slope of-4 that passes through the line

$y = -4x + b\\1 = -4(-2) + b\\1 = 8+ b\\b = -7\\y = -4x - 7$

#5:

(-2, 3) (1, -1), $m = \frac{3-(-1)}{-2-1} = \frac{-4}{3}, 3 = \frac{8}{3} + b, b = \frac{1}{3}, y = \frac{-4x}{3} + \frac{1}{3}$

(-3, 1) (1, 4), $m = \frac{4-1}{1-(-3)} =\frac{3}{4}, 4 = \frac{3(1)}{4} + b, y = \frac{3}{4}(x) + \frac{13}{4}$

(0, 2) (3, -2) $m = \frac{2-(-2)}{0-3} = \frac{-4}{3} , 2 = b, y = \frac{-4}{3}(x) + 2$

Since lines c and b have negative reciprocal slopes, they are perpendicular

#6:

a: y = -4x + 7

b: x = 4y + 2, $y = \frac{x}{4} - \frac{1}{2}$

c: -4y + x = 3, $y = \frac{x}{4} - \frac{3}{4}$

since lines a and c have negative reciprocal slopes, they are perpendicular

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3 years ago