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sergiy2304 [10]
3 years ago
11

The mean amount of water in 5 containers is 620 ml the total amount of water in 4 q of the containers is 2750 what is the amount

of water in the fifth container
Mathematics
2 answers:
damaskus [11]3 years ago
7 0

Answer:

350 ml

Step-by-step explanation:

The mean water in five containers = 620 ml

Mean of five container = total water in five container /5 = 620 ml

Total water in five container = (620 ml x 5)  

= 3100 ml

Container 1 + Container 2 + Container 3+ Container 4+ Container 5 = 3100 ml--------------Equation (1)

Water in four containers = 2750 ml  

This means ,  

Water in four containers = Container 1 + Container 2 + Container 3+ Container 4 = 2750 ml

Substituting this in equation 1, we get  

2750 ml + Container 5 = 3100 ml

Container 5 = 3100 ml -2750 ml

= 350 ml,  

Thus , water in fifth container = 350 ml.  

EleoNora [17]3 years ago
6 0
<span>The <u>correct answer</u> is:

350 ml.

Explanation<span>:

Let x be the amount in the fifth container.

The mean is found by adding all of the amounts together and dividing by the number of containers (in this problem, 5). We know that the total from the other 4 containers is 2750; add this to x, our unknown number. Then we divide by 5 to arrive at our answer of 620.

Algebraically,
</span></span>\frac{2750+x}{5}=620<span><span>

To solve, multiply both sides by 5:
</span></span>\frac{2750+x}{5}\times 5=620\times 5&#10;\\&#10;\\2750+x=3100<span><span>

Subtract 2750 from both sides:
 2750+x-2750=3100-2750
x=350.

There are 350 ml in the fifth container.</span></span>
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Samantha and Mia are 13 km apart from each other.

<h3>What is Pythagorean ?</h3>

A right triangle's squared sides add up to the hypotenuse's squared length, according to the Pythagorean Theorem.

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You need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture. How much
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Answer:

A. 605 mL of the 35% solution

B. 55 mL of the 95% solution

Step-by-step explanation:

It is given that, you need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture.

Let x and y be the amount of 35% alcohol solution and 95% alcohol solution (in mL) respectively.

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