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3 years ago

6.48> 6.4_1> 6.470 whats the unknown digit to make the statement true

Mathematics

1 answer:

Triss [41]3 years ago

8 0

The unknown digit is 7 because 6.471 is greater than 6.470 and less than 6.48.

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Consider the following data set: {4, 5, 6, 7, 10}. If you remove one of the numbers from the list, then the mean increases and t

Sauron [17]

Answer:

Step-by-step explanation:

Right now, the mean is 6.4 and the median is 6. If you take away 6, the mean would be 6.5 and the median will stay the same. The median will stay the same because when there is no middle number, you add the two closest numbers and divide by two.

Hope it helped:)

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2 years ago

Helpppp !<br> expand and simplify (x+y) (x+y)

DaniilM [7]

Answer:

Step-by-step explanation:

(x+y) (x+y)

=x^2+xy+yx+y^2

=x^2+2xy+y^2

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4 0

3 years ago

Read 2 more answers

The gum you like is on sale. it is regularly priced at $1.59.

Gemiola [76]

Answer:

The required equation is c = 1.59 - s

Step-by-step explanation:

Here, s represents the sales price per pack and c represents the cost saving,

Also, the regular price per pack = $ 1.59,

Since,

Cost saving = Regular price - sales price

⇒ c = 1.59 - s

Which is the required equation that is used to determine how much money is saved if the pack is bought today.

3 0

3 years ago

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What’s is the answer

kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

$(x^{2} )^{3} = x^6$

$(x^{3} )^5=x^{15}$

When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

$(x^{2} )(x^{3})=x^{5}$

$(x^{1} )(x^{2})=x^{3}$

$(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}$

You multiply 3 into each exponent in the numerator and the denominator

$\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

$\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}$

When you have something like this:

$\frac{x^{2}}{x^5}$

You subtract the exponents together, so:

$\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}$

Your answer is the second option

3 0

3 years ago

A medical study investigated the effect of calcium and vitamin supplements on the risk of older Americans for broken bones. A to

timofeeve [1]

Answer:

$\frac{37}{389}$

Step-by-step explanation:

Given that a medical study investigated the effect of calcium and vitamin supplements on the risk of older Americans for broken bones. A total of 389 older Americans who lived at home and were in good health were studied over a three-year period. While all of the 389 people took in at least 700 milligrams of calcium and 200 units of vitamin D through their normal diet, 187 of them were given additional supplements containing 500 milligrams of calcium citrate and 70 units of vitamin D daily. Of the 187 who took additional supplements, 11 of them suffered broken bones over the three-year period. Of the 202 older Americans who did not take the additional supplement, 26 of them suffered broken bones over the study period.

Group I Group II Total

n 187 202 389

favour x 11 26 37

The fraction of older Americans who were included in the study suffered broken bones during the three-year period

=Total x/total n

= $\frac{37}{389}$

4 0

3 years ago