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Gnom [1K]
4 years ago
5

On the track and field team,

Mathematics
2 answers:
defon4 years ago
6 0

Answer:

It could be anywhere from eight to 15 members.

Step-by-step explanation:

Answer:

A. Count the members on each team

   Hurdles  = ⅜ × 40 = 3 × 5 = 15

Long jump = ⅘ × 40 = 4 × 8  = 32

Let's look at the two extremes.

B. Most people will compete in only one event

Then the teams will overlap by seven members (Figure 1).

C. All those in Hurdles compete in the Long Jump

Then 15 members will compete in both Hurdles and Long Jump (Figure 2).

Natali5045456 [20]4 years ago
6 0

Answer:

12 do both hurdles and long jump

Step-by-step explanation:

3/8 of the team does hurdles, so that number is 3/8·40 = 15.

Of those 15, 4/5 do long jump, so there are ...

4/5·15 = 12 . . . hurdlers who do long jump

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Simplify -3p^3+5p+(-2p^2) +(-4) -12p +5 -(-8p^3)
GenaCL600 [577]

Simplify the following:

8 p^3 - 3 p^3 - 2 p^2 + 5 p - 12 p - 4 + 5

Grouping like terms, 8 p^3 - 3 p^3 - 2 p^2 + 5 p - 12 p - 4 + 5 = (-3 p^3 + 8 p^3) - 2 p^2 + (5 p - 12 p) + (-4 + 5):

(-3 p^3 + 8 p^3) - 2 p^2 + (5 p - 12 p) + (-4 + 5)

8 p^3 - 3 p^3 = 5 p^3:

5 p^3 - 2 p^2 + (5 p - 12 p) + (-4 + 5)

5 p - 12 p = -7 p:

5 p^3 - 2 p^2 + -7 p + (-4 + 5)

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Answer: 5 p^3 - 2 p^2 - 7 p + 1

7 0
3 years ago
What is the slope of he line through (-7,-2) and (-6,7)
lakkis [162]
The slope of the line is 9, so on a graph you would go up 9 over 1
3 0
3 years ago
Micah is twice as old as Richard. Richard is four times as old as Ken. Ken is six years old. How old is Micah?
Lelu [443]

Answer:

Step-by-step explanation:

Micah is 48 years old.

E.

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5 0
3 years ago
Read 2 more answers
Look at pic and answer pls
PtichkaEL [24]

(a)  x^{-5}

(b)  3x^{-7}

(c)  $\frac{4}{3}x^4

Solution:

To write each of the given expression in the form ax^n:

(a)  \frac{x^3}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

$\frac{x^3}{x^8}=x^{3-8}

$\frac{x^3}{x^8}=x^{-5}

(b) \frac{6x}{2x^8}

Divide numerator and denominator by the common factor 2, we get

$\frac{6x}{2x^8}=\frac{3x}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

      $=3x^{1-8}

$\frac{6x}{2x^8} =3x^{-7}

(c)  \frac{28x^6}{21x^2}

Divide numerator and denominator by the common factor 7, we get

$\frac{28x^6}{21x^2}=\frac{4x^6}{3x^2}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

        $=\frac{4}{3}x^{6-2}

$\frac{28x^6}{21x^2}=\frac{4}{3}x^4

8 0
3 years ago
Describe which of the two points lies on the graph of the line<br> Y-x=4<br> A. 9,5<br> B. 5,9
klasskru [66]
B. 5, 9

x = 5
y = 9

y - x = 4

(9) - (5) = 4

True

hope this helps
4 0
3 years ago
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