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4 years ago

Multiply. What is the value of the first partial product? 26 × 107

Mathematics

1 answer:

ehidna [41]4 years ago

8 0

1<u />
4 cross this out
107
* 26
------------------
642
+2140
-----------------
2782

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A rectangular storage container with an open top is to have a volume of 10 cubic meters. The length of its base is twice the wid

drek231 [11]

Answer:163.54$

Step-by-step explanation:

Given data

Volume of Storage(V)= ${10m^3}$

Length=2breadth

Let Length be L,Breadth be & height be H

therefore

10=LBH

Now substitutes the values

10=2 ${B^2}H$

5= ${B^2}H$

Now cost for base is ${C_1}=2{B^2}\times10$

Cost for side walls is ${C_2}={2LH}\times6+2BH}\times6$

Now total cost(C)= ${C_1}+{C_2}$

C=20 ${B^2}H$ + ${2LH}\times6$ + $2BH}\times6$

C=20 ${B^2}H$ +24BH+ $12BH$

C= $20{B^2}+36B\times\frac{5}{B^{2}}$

Now Differentiating With respect to Breadth to get minimum cost

$\frac{\mathrm{d} C}{\mathrm{d} B}=0$

$we\ get\ B=\sqrt[3]{4.5}=1.65m$

$L=3.30m$

$H=1.836m$

and mimimum cost C

${C=163.54\$}$

7 0

4 years ago

How to solve integers problems with big numbers

brilliants [131]

Answer:

$\Huge \boxed{-3}$

Step-by-step explanation:

To solve this problem, first you have to use add & subtract integers from left to right. Additive inverse is a opposite of a number. Additive inverse are the same distance from zero. The absolute value are the same.

First, add & subtract numbers from left to right.

$\displaystyle -21+18=-3$

Therefore, the correct is -3.

<h2>Hope this helps!</h2><h2 /><h2>Have a wonderful blessing day! :)</h2><h2 /><h2>Good luck! :)</h2>

3 0

3 years ago

A batch of 40 parts contains six defects. If two parts are drawn randomly one at a time without replacement, what is the probabi

adell [148]

Answer:

a) Therefore, the probability is P=1/52.

b) Therefore, the probability is P=9/400.

Step-by-step explanation:

We know that a batch of 40 parts contains six defects.

a) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time without replacement.

The probability for the first is 6/40.

The probability for the second is 5/39.

We get:

$P=\frac{6}{40}\cdot \frac{5}{39}\\\\P=\frac{1}{52}$

Therefore, the probability is P=1/52.

b) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time with replacement.

The probability for the first is 6/40.

The probability for the second is 6/40.

We get:

$P=\frac{6}{40}\cdot \frac{6}{40}\\\\P=\frac{9}{400}$

Therefore, the probability is P=9/400.

6 0

3 years ago

Jason estimates that his car loses 12% of its value every year. The initial value is $12,000. Which best describes the graph of

lbvjy [14]

The answer is 0.12 times x and the answer you get from that, just subtract it from 12,000

7 0

4 years ago

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What is the product? Assume x ≠ 0. 2x^2/3{6/x} 3x 4x 3x2 4x2

Serjik [45]

Answer:

Step-by-step explanation:

The given product is;

$\frac{2x^2}{3}(\frac{6}{x})$

This is the same as;

$\frac{2x^2\times 6}{3\times x}$

We cancel out the common factors to obtain;

$\frac{2x\times 2}{1\times 1}$

Multiply out to obtain;

$\frac{4x}{1}$

Simplify

$4x$

The second option is the correct choice.

7 0

3 years ago

Read 2 more answers