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Sav [38]
3 years ago
6

PLEASE HELP!!! ANYONE???

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
7 0
We can eliminate choice C because our parabola is not upside down.  The way I determined which one it was was by picking a point on the graph and testing the x value of the point in the equation.  If the y value on the graph was the same as the y value on my calculator, then I chose the right one.  Let me give you an example of what doesn't work first.  Let's pick (3, 2) from the graph.  Let's test that point in choice D.  Filling in x = 3, y should = 2 if that's the right equation.  \frac{1}{2}(3^2)-3+2= \frac{7}{2}.  Our y coordinate is not 7/2, it's 2.  Let's try A: \frac{1}{3}(3^2)-3-2=-2.  Again, our y value is 2, not -2.  Let's try B: \frac{1}{3}(3^2)-3+2=2.  See how that works?  Your choice is B.
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give an example of a convergent infinite series whose sum equal 3/5. explain how you know your series converges and write out wo
krek1111 [17]

Answer:

The series 1/5, 2/15, 4/45, 8/135... converges and sums up to 3/5

Step-by-step explanation:

Consider the infinite geometric series

1/5, 2/15, 4/45, 8/135...

With first term, a=1/5

common ratio, r = ⅔

The series converge because the common ratio, |r|<1.

The sum to infinity of a geometric series, S= a/(1-r)

S= 1/5 ÷ (1-⅔) = 1/5 ÷ 1/3 = 3/5

Therefore, the geometric series 1/5, 2/15, 4/45, 8/135... sums up to 3/5.

5 0
3 years ago
After eating at the restaurant,Joan,Melanie , and Sam decide to divide the bill evenly. If each person paid 37 dollars, what was
Nitella [24]

Answer:

$111

Step-by-step explanation:

37x3 = 111

111/3 =37

8 0
3 years ago
What is y to the 2 power = 81
iren [92.7K]

Answer:9

Step-by-step explanation:

6 0
3 years ago
What are 3 consecutive integers whose product is -120
iren2701 [21]
Consecutive integers are 1 apart
x,x+1,x+2
(x)(x+1)(x+2)=-120
x^3+3x^2+3x=-120
add 120 to both sides
x^3+3x^2+3x+120=0
factor
(x+6)(x^2-3x+20)=0
set each to zero

x+6=0
x=-6

x^2-3x+20=0
will yeild non-real result, discard
x=-6
x+1=-5
x+2=-4
the numbers are -4,-5,-6



use trial and error and logic
factor 120
120=2*2*2*3*5
how can we rearange these numbers in (x)(y)(z) format such that they multiply to 120?
obviously, the 5 has to stay since 2*5=10 which is out of range
so 2*2*2*3 has to arrange to get 3,4 or 4, 6 or 6,7
obviously, 7 cannot happen since it is prime
3 and 4 results in in 12, but 2*2*2*3=24
therfor answer is 4 and 6
they are all negative since negaive cancel except 1

the numbers are -4,-5,-6
5 0
3 years ago
Work out (5x10³) x (9x10)
nasty-shy [4]

Answer:

4.5 × 10^5 or 450000 :)))))

6 0
3 years ago
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