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Sav [38]
3 years ago
6

PLEASE HELP!!! ANYONE???

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
7 0
We can eliminate choice C because our parabola is not upside down.  The way I determined which one it was was by picking a point on the graph and testing the x value of the point in the equation.  If the y value on the graph was the same as the y value on my calculator, then I chose the right one.  Let me give you an example of what doesn't work first.  Let's pick (3, 2) from the graph.  Let's test that point in choice D.  Filling in x = 3, y should = 2 if that's the right equation.  \frac{1}{2}(3^2)-3+2= \frac{7}{2}.  Our y coordinate is not 7/2, it's 2.  Let's try A: \frac{1}{3}(3^2)-3-2=-2.  Again, our y value is 2, not -2.  Let's try B: \frac{1}{3}(3^2)-3+2=2.  See how that works?  Your choice is B.
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Answer:

x = 12

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Step-by-step explanation:

First let's find the value of each deposit until the 10th in relation to x and y:

1st: x

2nd: y

3rd: x + y

4th: x + 2y

5th: 2x + 3y

6th: 3x + 5y

7th: 5x + 8y

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10th: 21x + 34y

Now, we can write a system with two equations and two variables:

2x + 3y = 90

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From the first equation: x = (90 - 3y)/2

Using this value of x in the second equation, we have:

21*(90 - 3y)/2 + 34y = 1000

945 - 31.5y + 34y = 1000

2.5y = 55

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Now we can find x:

x = (90 - 3*22)/2 = 12

Now, summing all the deposits, we have a total of 55x + 88y, which is equal to 55*12 + 88*22 = $2596

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