Answer:
2(x + y)² - 9( x + y ) -5 = 0
⇒2(x + y)² - 10 (x+y) +1(x+y) -5 = 0
⇒2(x+y)(x + y - 5 ) + 1(x + y -5 ) = 0
taking (x + y -5 ) common ,
⇒(x + y -5 )[2(x + y) + 1] =0
⇒(x + y -5)(2x + 2y +1) =0
hope , you got this
Answer:
Well the answer to a) is (x - 3)(x + 1) and the answer to b) is (x + 4)(x - 2)
I don't really know how to describe it because I can do factorials in my head like it is nothing.
Answer:
#9
I can't write out the whole proof here.
it bisects, so we know BCA is congruent to DCA
abc being congruent to adc is given
AC = AC because it is a singular side
AAS
then the lines are congruent by CPCTC
Answer:
Step-by-step explanation:
For his birthday, Mr. Moore and three of his friends went to a movie. This means that they are 4 persons
They each got a ticket for $7.00 and the same snack from the concession stand. This means that the total cost of the tickets would be 4 × 7 = $28
If Mr. Moore's mom paid $42 for the group's tickets and snacks, it means that total cost of tickets + total cost of snacks = $42
Let the cost of each snack be $x
Since they are 4 persons and total cos of snacks and tickets is $42,
Total cost of snack will be 4 × x =
Total cost of ticket will be 4 × 7. So
(4 × x) +(4 × 7) = 42
Factorising 4, the expression becomes
4(x + 7) = 42
Solving the equation,
4x + 28 = 42
4x = 42 - 28 = 14
x = 14/4 = 3.5
Each snack cost $3.5
The 4 snacks cist $14