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Kay [80]
3 years ago
7

4/n = 4/5 a. n=5 b. n=5/16 c. n= 3 1/5 d. n= 50

Mathematics
1 answer:
Tanya [424]3 years ago
8 0

Answer:

The answer A) n=5

Step-by-step explanation:

Find the least common multiple.

The left denominator is "N"

The right denominator is "5"

That's how you get the answer N=5

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The amount of warpage in a type of wafer used in the manufacture of integrated circuits has mean 1.3 mm and standard deviation 0
valina [46]

Answer:

a) P(\bar X >1.305)=P(Z>\frac{1.305-1.3}{\frac{0.1}{\sqrt{200}}}=0.707)

And using the complement rule, a calculator, excel or the normal standard table we have that:

P(Z>0.707)=1-P(Z

b) z=-0.674

And if we solve for a we got

a=1.3 -0.674* \frac{0.1}{\sqrt{200}}=

So the value of height that separates the bottom 95% of data from the top 5% is 1.295.

c) P( \bar X >1.305) = 0.05  

We can use the z score formula:

P( \bar X >1.305) = 1-P(\bar X

Then we have this:

P(z< \frac{1.305-1.3}{\frac{0.1}{\sqrt{n}}}) = 0.95

And a value that accumulates 0.95 of the area on the normal distribution z = 1.64 and we can solve for n like this:

n = (1.64*\frac{0.1}{1.305-1.3})^2= 1075.84 \approx 1076

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

Let X the random variable that represent the amount of warpage of a population and we know

Where \mu=1.3 and \sigma=0.1

Since the sample size is large enough we can use the central limit theorem andwe know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

P(\bar X >1.305)=P(Z>\frac{1.305-1.3}{\frac{0.1}{\sqrt{200}}}=0.707)

And using the complement rule, a calculator, excel or the normal standard table we have that:

P(Z>0.707)=1-P(Z

Part b

For this part we want to find a value a, such that we satisfy this condition:

P(\bar X>a)=0.75   (a)

P(\bar X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.674

And if we solve for a we got

a=1.3 -0.674* \frac{0.1}{\sqrt{200}}=

So the value of height that separates the bottom 95% of data from the top 5% is 1.295.

Part c

For this case we want this condition:

P( \bar X >1.305) = 0.05  

We can use the z score formula:

P( \bar X >1.305) = 1-P(\bar X

Then we have this:

P(z< \frac{1.305-1.3}{\frac{0.1}{\sqrt{n}}}) = 0.95

And a value that accumulates 0.95 of the area on the normal distribution z = 1.64 and we can solve for n like this:

n = (1.64*\frac{0.1}{1.305-1.3})^2= 1075.84 \approx 1076

6 0
3 years ago
If a 12 hour analog clock reads 8:00, what is the degree measure of the smaller angle formed by the minute and hour hands
ANTONII [103]

Answer:

Its probably 240

Step-by-step explanation:

If you divide 360 into 12 parts, you get 30 for each part, 8x30=240, so the answer is 240º I think, dont take my word for it though

3 0
3 years ago
Please help me. If you don't know the answer don't respond
olga_2 [115]

Answer:

1/3

Step-by-step explanation:

x  from 3 to 1 = 1/3

y  from 18 to 6 = 6/18 = 1/3

6 0
3 years ago
Standard deviation of a normal data distribution is a _______.
Keith_Richards [23]

Answer:

Measure of Data Dispersion

Step-by-step explanation:

Standard deviation is used to show the variation and dispersion in a group of data. It shows how separated the data's are to each other and how each data can be related to the other.

A normal data distribution are those group of data, that are distributed in a wide range. The standard deviation helps to to measure how they are been spread out.

Standard deviation does not measure the shape, quality, and center of data. This are measured with graphs, range, mean and median.

5 0
2 years ago
Read 2 more answers
Tickets to the spring festival are being sold online. the ticket price is $8 per person. the expression 8t + 2 represents the to
strojnjashka [21]

Answer:

32 because 8×4=32 that's why 33is the answer

4 0
3 years ago
Read 2 more answers
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