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solong [7]
3 years ago
14

How do you solve: -16(2r-7)=4(5-3r) Thank you for answering!

Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Exact Form - 23/5

Decimal Form - 4.6

Hope This Help's

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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
Graph A represents the function f(x)=^3 graph B and C are transformations of graph A
PolarNik [594]

Answer:

A3

Step-by-step explanatio

6 0
2 years ago
Find the equation of the line through point (−5,5) and perpendicular to y=59x−4
VARVARA [1.3K]

Answer:

Step-by-step explanation:

5 0
1 year ago
Two lines meet at a point that is also a vertex of an angle; the measurement of ∠AOF is 134°.
Stells [14]

Answer:

x and y are the same. they are both 99

Step-by-step explanation:

8 0
2 years ago
How do I answer this question
Gnom [1K]
First you have to make it multiplication so you flip 5/2 around and the two “2’s” will cancel each other so it will be 17/5 or 3 2/5
6 0
3 years ago
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