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torisob [31]
3 years ago
7

The speed of light in vacuum is 2.998x10^8 m/s. What is the speed in km/hr and mi/min?

Mathematics
2 answers:
diamong [38]3 years ago
6 0

Speed of light in vacuum = 2.998 x 10^8 m/s

1m = 1/1000 km and 1s = 1/3600 hr

Speed of light in vacuum = (2.998 x 10^8 x (1/1000) km) / (1/3600) hr

Speed of light in vacuum = 10.792 x 10^8 km/hr

Now

1km = 0.6213 mi

1hr = 60min

As Speed of light in vacuum = 10.792 x 10^8 km/hr

Speed of light in vacuum = 10.792 x 10^8 x (0.6213mi) / 60min

Speed of light in vacuum = 0.1117 x 10^8 mi/min

<span>Speed of light in vacuum = 11.17 x 10^6 mi/min</span>

KIM [24]3 years ago
5 0

1.08 x 10⁹ km/hr and 1.12 x 10⁷ mi/min.

<h3>Further explanation</h3>

<u>Given:</u>

The speed of light in vacuum is 2.998 x 10⁸ m/s

<u>Question:</u>

What is the speed in km/hr and mi/min (miles/minute)?

<u>Problem solving:</u>

We will solve the problem here about the conversion of length and time units.

To solve our case, consider the following unit length and time conversions.

Lenght (or Distance)

  • \boxed{ \ 1 \ km = 1,000 \ m \ }
  • \boxed{ \ 1 \ mile = 1,609.34 \ m \ }

Time

  • \boxed{ \ 1 \ hour = 60 \ minutes \ }
  • \boxed{ \ 1 \ minute = 60 \ seconds \ }
  • \boxed{ \ 1 \ hour = 3,600 \ seconds \ }

<u>Convert m/s to km/hr</u>

\boxed{ \ 2.998 \times 10^8 \ \frac{m}{s} \times \frac{1 \ km}{1,000 \ m} \times \frac{3,600 \ s}{1 \ hr} \ }

\boxed{ \ 2.998 \times 10^8 \times 3.6 \ \frac{km}{hr} \ }

\boxed{ \ 10.7928 \times 10^8 \ \frac{km}{hr} \ }

Adjust it again to fit the scientific notation.

\boxed{ \ 1.07928 \times 10^9 \ \frac{km}{hr} \ }

After rounding to 2 decimal places, the result is \boxed{\boxed{ \ 1.08 \times 10^9 \ \frac{km}{hr} \ }}

<u>Convert m/s to mi/min</u>

\boxed{ \ 2.998 \times 10^8 \ \frac{m}{s} \times \frac{1 \ mile}{1,609.34 \ m} \times \frac{60 \ s}{1 \ min} \ }

\boxed{ \ 2.998 \times 10^8 \times 0.0373 \ \frac{mi}{min} \ }

\boxed{ \ 0.1118 \times 10^8 \ \frac{mi}{min} \ }

Adjust it again to fit the scientific notation.

\boxed{ \ 1.118 \times 10^7 \ \frac{mi}{min} \ }

After rounding to 2 decimal places, the result is \boxed{\boxed{ \ 1.12 \times 10^7 \ \frac{mi}{min} \ }}

<h3>Learn more</h3>
  1. Representation of .000025 in scientific notation brainly.com/question/10830549
  2. Gasoline efficiency in Europe  brainly.com/question/1504545
  3. About the engine displacement of Kawasaki Ninja brainly.com/question/5009365

Keywords: the speed of light in vacuum is 2.998 x 10⁸ m/s, what is the speed in km/hr and mi/min? hour, mile, minutes, conversion, length, time, the scientific notation

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Plz help me with this math and also explain
jasenka [17]

Step-by-step explanation:

<h2>[1]</h2>

  • SI = $250
  • Rate (R) = 12\sf \dfrac{1}{2} %
  • Time (t) = 4 years

\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\

\longrightarrow \tt { 250 \times 100 = P \times 50} \\

\longrightarrow \tt { 25000 = P \times 50} \\

\longrightarrow \tt { \dfrac{25000}{50} = P } \\

\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\

Therefore principal is $500.

<h2>__________________</h2>

<h2>[2]</h2>

  • 2/7 of the balls are red.
  • 3/5 of the balls are blue.
  • Rest are yellow.
  • Number of yellow balls = 36

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\

\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\

\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\

\longrightarrow \tt{ 31x + 1260= 35x} \\

\longrightarrow \tt{ 1260= 35x-31x} \\

\longrightarrow \tt{ 1260= 4x} \\

\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\

\longrightarrow \underline{\boxed{  \tt { 315 = x }}} \\

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\

\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\

\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\

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