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Gelneren [198K]
3 years ago
14

WILL GIVE BRAINLIEST TO FIRST ANSWER

Mathematics
1 answer:
algol [13]3 years ago
6 0

Answer:

Step-by-step explanation:

1st picture on left: no solution

2nd picture on right infinitely many solutions

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Wayne is mixing paint.
LuckyWell [14K]

Answer:

176. Multiply 6 by 2 thirds.

Step-by-step explanation:

4 0
3 years ago
Solve the equation 2cos^2x = sin2x , giving your answer in terms of π. 0
Sveta_85 [38]
<span>2cos^2x = sin2x 2cos^2x = 2sin x cos x (2sin x cos x) / (2cos^2x) = 1 sin x / cos x = 1 tan x = 1 x = π/4</span>
8 0
3 years ago
Read 2 more answers
I need answers for those two questions please. ​
azamat

Answer:

Step-by-step explanation:

1.

sin R=15/39=0,3846

R≈23°

2.

tan 52°= 1,2799

3 0
3 years ago
Read 2 more answers
Solve the following<br>a) 2(5x-3)=24 what is x<br><br>b) 5(2x+1)=50
timama [110]
A) 2(5x-3)=24
*Distribute the 2*
10x-6=24
*Add 6 to both sides*
10x=30
*Divide both sides by 10*
ANS: x=3
b) 5(2x+1)=50
*Distribute the 5*
10x+5=50
*Subtract 5 from both sides*
10x=45
*Divide both sides by 10*
x=45/10
*Simplify by dividing numerator and denominator by GCF (5)
ANS: x=9/2

Hope this makes sense!
8 0
3 years ago
If y=x^2+kx-k for what values of k will the quadratic have 2 real solutions
xeze [42]

The key to answering this question lies in finding the discriminant b^2-4ac. If b^2-4ac is greater than zero, the quadratic equation will have 2 real solutions.

Typing out y=x^2+kx-k, we see that a=1, b=k and c = -k. The discriminant in this case is

b^2 - 4(a)(c), or k^2 - 4(1)(-k), or k^2 + 4k

For which k is this k^2 + 4k = 0? Factor k^2 + 4k, obtaining k(k+4) = 0; the roots of this are k=0 and k = -4.

Now set up a number line for k, drawing empty circles at k = 0 and k = -4. These two values divide the number line into three intervals:

(-infinity, -4), (-4, 0) and (0, infinity). Choose a test number for each interval:

-6 for the first, -2 for the second and 4 for the third. Determine whether k^2 + 4k > 0 for any of these test numbers:

(-6)^2 + 4(-6) = 36 - 24 = +12. Yes, the discriminant is + on the interval (-infinity, -4)

(-2)^2 + 4(-2) = 4 - 8 = -4. No, the discriminant is not + on (-4, 0).

(4)^2 + 4(4) = 32. Yes, the discrim. is + on (0, infinity).

So: The given quadratic will have two different, real roots on the two intervals (-infinity, -4) and (0, infinity).

4 0
3 years ago
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