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LiRa [457]
3 years ago
7

ALL THE POINTS I HAVE! PLEASE IM BEGGING YOU!

Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer:

Step-by-step explanation:

Download pdf
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An angle ha turned through 270 one-degree angels.What is the measurement of this angle in degrees ?
GenaCL600 [577]

Answer:

270 degree angle

Step-by-step explanation:

4 0
3 years ago
What is the x? what could the x be?
sineoko [7]
It would be x=3.50 because 8 divided by 4 is 2 and 14 divided by 4 is 3.5
7 0
4 years ago
Evaluate x-2y when x=3,y=-3
adelina 88 [10]

Answer: 9

Step-by-step explanation:

3-2x-3

2x-3=-6

3--6=3+6=9

8 0
3 years ago
Read 2 more answers
PLEASE CAN ANYONE HELP!!!
DiKsa [7]

Answer:

x = 3

y = 4  

hey, I am not 100% sure of the certainty of my answers, I am using what I remember about that topic but I do not know if it is right or wrong, I hope I have helped you, I did what I could.

Step-by-step explanation:

-3x + 2y = 23

5x + 2y = -17

X solution:

(you cancel the y)

-3x = 23

5x = -17

(you combine all the values above with those below)

2x = 6

(solve the ecuation normaly)

x = 6/2 = 3

Y solution:

(you replace the x)

-3(3) + 2y = 23

5(3) + 2y = -17

-9 + 2y = 23

15 + 2y = -17

(you combine all the values above with those below)

6 + 4y = 6

(solve the ecuation normaly)

4y = 0

y = 4  

(I do not really know if the answer here is 0 or 4 since when passing the 4 to divide it would be 0/4 and I do not understand very well how that is solved)

6 0
3 years ago
Read 2 more answers
Solve for all complex roots (2x^10)+(3x^9)-(5x^8)-(9x^7)-(x^6)+(3x^5)+(7x^4)+(9x^3)-(x^2)-(6x)-2
fomenos

Solve for x by completing the square:

2 x^10 + 3 x^9 - 5 x^8 - 9 x^7 - x^6 + 3 x^5 + 7 x^4 + 9 x^3 - x^2 - 6 x - 2 = 0

The left hand side factors into a product with five terms:

(x - 1)^2 (x + 1)^3 (2 x + 1) (x^2 - 2) (x^2 + 1) = 0

Split into five equations:

(x - 1)^2 = 0 or (x + 1)^3 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Take the square root of both sides:

x - 1 = 0 or (x + 1)^3 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Add 1 to both sides:

x = 1 or (x + 1)^3 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Taking cube roots gives 0 times the third roots of unity:

x = 1 or x + 1 = 0 or x + 1 = 0 or x + 1 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x + 1 = 0 or x + 1 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x + 1 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x = -1 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x = -1 or 2 x = -1 or x^2 - 2 = 0 or x^2 + 1 = 0

Divide both sides by 2:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x^2 - 2 = 0 or x^2 + 1 = 0

Add 2 to both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x^2 = 2 or x^2 + 1 = 0

Take the square root of both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x = sqrt(2) or x = -sqrt(2) or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x = sqrt(2) or x = -sqrt(2) or x^2 = -1

Take the square root of both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x = sqrt(2) or x = -sqrt(2) or x = i or x = -i

There are {2} duplicate solutions:

Answer: x = -1 or x = 1 or x = -1/2 or x = -i or x = i or x = sqrt(2) or x = -sqrt(2)

3 0
3 years ago
Read 2 more answers
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