Answer:
x=2, y=-1, z=3
Step-by-step explanation:
The system shown in the attached picture can be solved using any method you wish
I think that the best way to go is by using the subtraction method,
First multiply the equation x+y+z=4 by 2, then sum it to the second equation.
This gives another equation: 4x+z=11.
If we subtract the first eq. with the third, we have another eq. -5x+z=-7.
Lest sum the 2 new founded equations, to obtain the following result: -9x=-18
thus, we obtain x=2
Next lets go backwards in the prior eq -5x+z=-7, with x=2, we obtain that z=3
Now in the first equation (x+y+z=4) we can substitute x=2, z=3 to obtain y value.
Answer:
Step-by-step explanation:
There are non-distinct sums that can be achieved when rolling two fair sided dice.
The smallest of these sums is and the largest of these sums is . Within this range, there exists only one perfect cube, .
Count how many ways we can achieve a sum of 8 with two dice:
Thus the probability the total score (sum) will be a perfect cube when rolling two fair six-sided dice is equal to
Im pretty sure it would be 10??? if you are putting it as a subtraction problem if not i would try wording it more clearly
Answer:
no i only get a 30 second vid and then get the answer
The answer to that question is 250.