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prohojiy [21]
3 years ago
10

Are all right triangles similar

Mathematics
1 answer:
scZoUnD [109]3 years ago
4 0
I think the answer is no. Not all right angles are similar. For them to be similar, one triangle should be an enlargement of the other triangle. The dimensions of the triangles should have a constant ratio for the two shapes. This is not true for all right triangles.
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Please help me ! Today 11/6/2020 :(
dangina [55]
I believe the answer is c, TSR
5 0
3 years ago
There are 165 counters in a bag. Each counter is either black or white.
Nostrana [21]

6:5

  • there are 165 counters in the bag.

let the white counter be x

  • the black counter = 2x

2x + x = 165

  • 3x=165

divide both sides by 3

  • x=55

there are 55 white counters in the bag

165-55=110

OR

2x= 165

divide both sides by 2

x= 110

  • there are 110 black counters in the bag
  • Martine takes 40%of the black counter

40%= 40/100×110

= 44.

  • 44 black counters was taken out of the bag
  • then there would be 66 black counters left I.e(110-44=66)

▪︎ there would be 66 black and 55 white counters in the bag.

  • ratio of black counters to the white counter = 66:55
  • reduced to the lowest term = 6:5 ( 11 divides 66 and 55 Into 6 and 5)

• the answer is 6:5

8 0
3 years ago
How do i find the area of a triangle if the base is x and the height is 2x
yuradex [85]

Answer:

A= (1/2)(X)(2X)

(1/2)(2X^2)

= (2X^2)/2

6 0
3 years ago
Finding an Equation of a Tangent Line In Exercise, find an equation of the tangent line to the graph of the function at the give
LenaWriter [7]

Answer:

Equation of tangent will be y=\frac{x}{e}

Step-by-step explanation:

We have given the function y=x^2e^{-x}

We have to find the equation of tangent at the point (1,\frac{1}{e})

Equation of tangent is equal to \frac{dy}{dx}

So \frac{dy}{dx}=x^2\frac{d}{dx}e^{-x}+e^{-x}\frac{d}{dx}2x=-x^2e^{-x}+2e^{-x}

Now we have given point (1,\frac{1}{e})

So putting these points in the equation of tangent

\frac{dy}{dx}=-1^2e^{-1}+2e^{-1}

\frac{dy}{dx}=\frac{1}{e}

Now equation of tangent passing through (1,\frac{1}{e})

y-\frac{1}{e}=\frac{1}{e}(x-1)

y=\frac{x}{e}-\frac{1}{e}+\frac{1}{e}=\frac{x}{e}

4 0
3 years ago
A functionf(x) is graphed on the coordinate plane.
mario62 [17]

Answer:

y = -1/2x + b  meaning f(x) = -1/2x + b

Step-by-step explanation:

Use two points on the graph that you can find the value of  or use Slope = raise/run

let use points (2,0) and (0, 1)

slope = (change in the y-value)/(change in the x-value.

slope = (1 - 0)/(0 - 2)

slope = 1/-2 or -1/2

Or starting at point (2, 0) the run(x movement) = -2 and the raise is 1.

slope = raise/run

slope =  1/-2 or -1/2

Using one point (2,0) and the slope of -1/2, substitute into the slope intersect form, y = mx + b, and solve for "b" .

y= mx + b

0 = -1/2(2) + b

0 = -1 + b

1 = b

Now write your equation: y = mx +b where m = -1/2 and b = 1

y = -1/2x +b

3 0
3 years ago
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