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Volgvan
3 years ago
11

What characteristic of the depositional environment influence

Geography
1 answer:
madam [21]3 years ago
7 0

Answer:

The characteristic of the depositional environment affects the properties of sedimentary rocks are as follows-

(1) <u>Lithology-</u> It describes the constituent mineral and the type of texture these crystals have, which forms a sedimentary rock. These minerals occur in a certain depositional environment. When the weathered materials are derived and transported to some other place, then it forms a stable one in a fixed environment as the rocks are subjected to compaction and lithification, The environment in which these minerals have led to the formation of these rocks can be determined.

(2) <u>Structure-</u> There are various structures that occur in rock, such as ripple marks, cross-bedding that highlights the flow direction of water and wind. Many structures like slickensides, folding, faulting occurs in the sedimentary rocks that are formed due to tectonic activities. These structures can easily be identified and their environment of deposition can also be determined.

(3) <u>Fossil content-</u> Fossils are found to be embedded in the sedimentary rocks. The shells of organisms after death are accumulated at the bottom of the ocean. As a result of this, these shells are covered with the sediments and after millions of years, turn into fossils. For example, Sandstone, Limestone, and shale comprised of various types of shells. These fossils are found to be deposited in a shallow marine environment.

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Earth is ________.
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a.the smallest planet

<u>b.one of the inner planets</u>

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Explanation:

if you choose options a it's wrong because the smallest planet is mercury

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4 years ago
Why would countries invade each other in the middle east
Sliva [168]

Answer:

In order to maintain power over another.

Explanation:

Countries invade each other in the middle east in order to maintain its power and interests in the region. This region is an area of competition for global powers, such as Russia and the United States of America and conflict also occur between rivalries, such as Qatar versus Saudi Arabia and Iran and Saudi Arabia. So to claim power and protect interests in the region conflict occur in the middle east.

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3 years ago
Wetlands can play a significant role in removing fertilizer residues from rain runoff and groundwater; one way they do this is t
Lana71 [14]

The question is incomplete, the complete question is;  

Wetlands can play a significant role in removing fertilizer residues from rain runoff and groundwater; one way they do this is through denitrification, which converts nitrate ions to nitrogen gas:

2NO_3^-(aq) + 5 CO(g) + 2 H+(aq)  N2(g) + H2O(l) + 5 CO2(g)

Supposed 200.0 g of NO_3^- flows into a swamp each day. What volume of N2 would be produced at 17 deg C. and 1.00 atm if the denitrification process were complete? What volume of CO2 would be produced? Suppose the gas mixture produced by the decomposition reaction is trapped in a container at 17 deg C; what is the density of the mixture if we assume that the total P = 1.00 atm?  

Answer:

See detailed solution below

Explanation:

First we must obtain the number of moles of NO3^- from

number of moles = mass/molar mass

mass of = 200g

molar mass of NO3^- = 62 g/mol

number of moles = 200g/62g/mol = 3.23 moles

From the reaction equation;

2 moles of NO3^- yields 1 mole of N2

3.23 moles yields 3.23 * 1/2 = 1.6 moles

From

PV = nRT

V = nRT/P

V = 1.6 * 0.082 * 290/1

V= 38 L

Then;

From the equation also;

2 moles of  NO3^-  yields 5 moles of CO2

3.23 moles of NO3^-  yields 3.23 * 5/2 = 8.1 moles

So,

PV=nRT

V = nRT/P

V= 8.1 * 0.082 * 290/1

V= 192.6 L

Lastly

The temperature of the mixture is 17 degrees Celsius and the pressure of the mixture is 1 atm

the total number of moles of both gases = 1.6 + 8.1 = 9.7 moles

Volume of the mixture = nRT/P = 9.7 *0.082*290/1 = 230.67 L

Mass of N2 = 1.6 moles * 28 g/mol = 44.8 g

Mass of CO2 = 8.1 moles * 44 g/mol = 356.4 g

Total mass of gases = 44.8 + 356.4 = 401.2 g

Density of mixture = mass/volume = 401.2g/230.67 L

Density of mixture = 1.74 g/L

8 0
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