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bixtya [17]
3 years ago
8

What is the value of -3 to the second power +(-4+7)(2)

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0

Answer:

15

Step-by-step explanation:

=> (-3)²+(-4+7)(2)

=> 9+(3)(2)

=> 9+6

=> 15

You might be interested in
John took all his money from his savings account. He spent $88 on a radio and 1/4 of what was left on presents for his friends.
gayaneshka [121]

Answer:

$968

Step-by-step explanation:

x= the money John originally had in his savings account

The statement says that John spent $88 on a radio and 1/4 of what was left on presents for his friends. This means that the remaining money is 3/4 of the total amount minus the money spent on the radio:

3/4(x-88)

Then, it says that of the money remaining, John put 4/11 into a checking account and the last remaining $420 was left to charity. Since, he spent 4/11 of the remining 3/4(x-88), the remaining is 7/11 of that and that remaining is equal to $420 that was the money left at the end:

7/11(3/4(x-88))= 420

21/44(x-88)=420

21/44x-42=420

21/44x=462

x=968

According to this, the money that John originally had in his savings account was $968.

He spent $88 on a radio: 968-88= 880

1/4 of what was left on presents for his friends: 880/4= 220

880-220=660

Of the money remaining, John put 4/11 into a checking account: 660*(4/11)=240

the last remaining $420 was left to charity: 660-240= 420

6 0
3 years ago
For parts a and bâ, use technology to estimate the following. âa) The critical value of t for a 90â% confidence interval with df
rjkz [21]

Answer:

a) For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

b) For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

Part a

For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

Part b

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

3 0
3 years ago
Evaluate:<br> -9 + 25 - (-10) + (-6)
Minchanka [31]
-9 is a negative number, so plus 25, it would be 16. The minus sign and the negative sign of -10 cancel out, so it is plus 10, ending up with 26. Finally, the + and - becomes negative (positive times negative equals negative), so it is -6 and you’ll end up with a final answer of 20.
4 0
3 years ago
Read 2 more answers
= table shows a hot air balloon's height h, in feet, during a descent at various times t, in seconds.
denpristay [2]

Answer:

A. Slope is -12 feet per second

B. Yes, it is constant.

<u>Skills needed: Linear Equations, Substitution and Division</u>

Step-by-step explanation:

1) Solving Part A (we need to find the slope):

  • The slope is \frac{y_2-y_1}{x_2-x_1} --> y_1, y_2, x_1, and x_2 are all values from the table. We know that the left column is the x-values, and the right column is the y-values as that is the conventional way of depicting them.

2) Using the y-values of 1150 and 1090, and their corresponding x-values (5 and 10 respectively), we can get the slope:

- \frac{y_2-y_1}{x_2-x_1} ==> \frac{1090-1150}{10-5} ==> 1090-1150=-60, 10-5=5 ==> \frac{-60}{5}

\frac{-60}{5} =-12, so the slope is -12.

==================================================================

1) Part B (analysis)

We can see that no matter what 2 y-values and their corresponding x values we use, the slope always is the same. This means that the rate of change is constant.

8 0
2 years ago
Find the value of x. what is the relationship of these 2 angles? set up and solve an equation
tatiyna

Answer:

the relationship between these two angle is they r straight angle.

  • 101+3x+4=180°
  • 105+3x=180°
  • 3x=180-105
  • x=75/3
  • x=25°

hope it helps

<h2>stay safe healthy and happy.</h2>
5 0
3 years ago
Read 2 more answers
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