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Free_Kalibri [48]
3 years ago
6

Given collinear points A, B, and C, is the statement below true or false?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer:

True.

Step-by-step explanation:

As A, B and C are collinear,

the line  CAB = CB = CA + AB

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Geometry, please answer question ASAP
Pepsi [2]

Answer:

Figures A,D are polygons.

Reason:

Polygon is a closed figure with atleast three strange lines and angles.

7 0
3 years ago
What is the slope intercept form of the equation of 6x+5y=-15
Soloha48 [4]
Slope intercept form is \sf y=mx+b, where 'm' is the slope and 'b' is the y-intercept.

\sf 6x+5y=-15

Subtract 6x to both sides:

\sf 5y=-6x-15

Divide 5 to both sides:

\boxed{\sf y=-\dfrac{6}{5}x-3}
7 0
3 years ago
Anyone know the answer to this
Vesna [10]

Answer:

Part A:

- angle ACB= 60° (ABC equilateral triangle.)

- Angle ECD=EDC= (180°-32°)/2= 148/2= 74° (sum of angles in a triangle is equal to 180, and triangle ECD is isosceles since it's given that CE=DE.

- x= 180°-(60°+74°)

   = 180°-134°

   = 46°

x= 46°

Part B:

120°

3 0
2 years ago
(6) Give the equation of the line passing through the points (1,5) and (-2, 6) in
Bas_tet [7]

Answer:

⅓x + y = 5⅓

or

⅓x + y = 5.3333333

or

⅓x + y = 16/3

Step-by-step explanation:

Solve for slope using rise/run

Y2 - Y1 / X2 - X1

(6) - (5) / (-2) - (1)

1 / -3

Slope: -⅓

y = -⅓x + b

solve for b using one of the points

I'll be using (1,5)

Substitute the point into the equation

5 = -⅓(1) + b

5 = -⅓ + b (add ⅓ to both sides)

+⅓ +⅓

5⅓ = b

5⅓ can also be written as 16/3 or 5.333333

The equation is now:

y = -⅓x + 5⅓

Convert to standard form by adding ⅓x to both sides

y = -⅓x + 5⅓

+⅓x +⅓x

Solution: ⅓x + y = 5⅓

8 0
3 years ago
I need to get the left side to equal the right side. Keeping the right side alone and not changing it.
likoan [24]

<u>To prove the trigonometric equation:</u>

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

RHS=(\sin x+\cos x)(1-\sin x \cos x)

We know that \sin^2x +\cos^2x=1, substitute this in place of 1.

       =(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)

Multiply each term of the first term with each term of the 2nd term.

       =\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x

Group like terms together.

       =\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x

       =\sin^3x +( 0)+(0) + \cos^3 x

       =\sin^3x + \cos^3 x

       = LHS

RHS = LHS

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

Hence proved.

7 0
3 years ago
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