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OlgaM077 [116]
3 years ago
15

Write the value of the underlined digit 6.54

Mathematics
2 answers:
marta [7]3 years ago
5 0
The 6 is in the ones place 
the 5 is in the tenths place 
the 4 is in the hundredths place 

hope it helps :D


LenKa [72]3 years ago
3 0
6 is in the ones place
.5 is in the tenths place
and the 4 in 6.54 is in the hundredths place
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Which of the following rational functions is graphed below?
frozen [14]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of t
natka813 [3]

Hello AljakeVillena!

\huge \boxed{\mathfrak{Question} \downarrow}

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

Given,

  • mass of crate = 50 kg
  • Force you pull it with = 450 N
  • Frictional force = 250 N
  • Acceleration = ?

__________________

Let's first find the total force/net force acting on the crate. The total force will be :-

  • 450 N - 250 N = <u>2</u><u>0</u><u>0</u><u> </u><u>N.</u>

We subtracted the forces because both the forces act on opposite directions.

__________________

Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..

  • Acceleration = Force/mass
  • a = F/m
  • a = 200/50
  • <u>a = 4 m/s²</u>

__________________

So, the acceleration of the crate is <u>4</u><u> </u><u>m/</u><u>s²</u><u>.</u>

__________________

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6 0
3 years ago
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
I need so much help with these two and quick if anybody can helpe out thanks.<br>​
lesya [120]

Answer:I need so much help with these two and quick if anybody can helpe out thanks.

Step-by-step explanation:

I need so much help with these two and quick if anybody can helpe out thanks.

6 0
2 years ago
Need help with this maybe question
Aleonysh [2.5K]

Answer:

the vertex is:

(2, -1)

Step-by-step explanation:

First solve the equation for the variable y

x^2-16y-4x-12=0

Add 16y on both sides of the equation

16y=x^2-16y+16y-4x-12

16y=x^2-4x-12

Notice that now the equation has the general form of a parabola

ax^2 +bx +c

In this case

a=1\\b=-4\\c=-12

Add (\frac{b}{2}) ^ 2 and subtract (\frac{b}{2}) ^ 2 on the right side of the equation

(\frac{b}{2}) ^ 2=(\frac{-4}{2}) ^ 2

(\frac{b}{2}) ^ 2=(-2) ^ 2

(\frac{b}{2}) ^ 2=4

16y=(x^2-4x+4)-4-12

Factor the expression that is inside the parentheses

16y=(x-2)^2-16

Divide both sides of the equality between 16

\frac{16}{16}y=\frac{1}{16}(x-2)^2-\frac{16}{16}

y=\frac{1}{16}(x-2)^2-1

For an equation of the form

y=a(x-h)^2 +k

the vertex is: (h, k)

In this case

h=2\\k =-1

the vertex is:

(2, -1)

6 0
3 years ago
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