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3 years ago

6

In ΔDEF, the measure of ∠F=90°, the measure of ∠E=32°, and FD = 9.6 feet. Find the length of EF to the nearest tenth of a foot.

2 answers:

monitta3 years ago

8 0

Answer:

EF=15.4 ft

Step-by-step explanation:

I got it right on delta math so ig its right

NeX [460]3 years ago

6 0

Answer:

$EF=15.4\ ft$

Step-by-step explanation:

we know that

In the right triangle DEF

$tan(E)=\frac{FD}{EF}$ ----> by TOA (opposite side divided by adjacent side)

substitute the given values

$tan(32^o)=\frac{9.6}{EF}$

solve for EF

$EF=\frac{9.6}{tan(32^o)}=15.4\ ft$

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Step-by-step explanation:

<u>Step 1: Solve using the first point</u>

<em>(2, 28)</em>

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<u>Step 2: Solve using the second point</u>

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$-5 = a(-1)^3 + b(-1)^2 + c(-1) + d$

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<u>Step 3: Solve using the third point</u>

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$220 = a(4)^3 + b(4)^2 + c(4) + d$

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<em>(-2, -20)</em>

$-20 = a(-2)^3 + b(-2)^2 + c(-2) + d$

$-20 = -8a + 4b - 2c + d$

<u>Step 5: Combine the first and fourth equations</u>

<u /> $28 - 20 = 8a - 8a + 4b + 4b + 2c - 2c + d + d$

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