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Serjik [45]
3 years ago
13

. For the function given, state the starting point for a sample period:

Mathematics
1 answer:
Aneli [31]3 years ago
8 0
I think the answer is π?
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Question 15 please. Thanks
horsena [70]
Ignore the decimal places and do 789x38 and you get 29982. Now all you have to do is put the decimal places back. Since 789 was 7.89 it had 2 decimal places and 38 had 1 you have to move 29982 three decimal places to the left making your final answer 29.982.
3 0
3 years ago
Y + 1/2 = 7/10 solve for y
ahrayia [7]
It would be 2/10 or 1/5 simplified
7 0
4 years ago
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a youth group earned $285 washing cars.The group's expenses were $79 . how much profit did the group make washing cars
kiruha [24]
206. Why can't they shorten the characters needed to 5?!
7 0
4 years ago
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What is the value of m in the equation 1/2m - 3\4n = 16 , when n = 8?
Rufina [12.5K]
1/2m -3/4n = 16

solve your system of equations.

n=8: (1/2)(m)+((−3)/4)(n)=16

Solve n=8 for n:

Substitute (8) for n in 1/2m+−3/4n=16:

1/2m+−3/4n=16

1/2m+−3/4(8)=16

1/2m−6=16(Simplify both sides of the equation)

1/2m−6+6=16+6(Add 6 to both sides)

1/2m=22

1/2m1/2 = 22 / 1/2(Divide both sides by 1/2)

m=44

8 0
3 years ago
Derivative of 2 tan^3(x)+5 csc^4(x) ?
Leni [432]

Answer:

f'(x) = 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]

Step-by-step explanation:

f' of tan(x) = sec²(x)

f' of csc(x) = -csc(x)cot(x)

General Power Rule: uⁿ = xuⁿ⁻¹ · u'

Step 1: Write equation

2tan³(x) + 5csc⁴(x)

Step 2: Rewrite

2(tan(x))³ + 5(csc(x))⁴

Step 3: Find derivative

d/dx  2(tan(x))³ + 5(csc(x))⁴

  • General Power Rule: 2 · 3(tan(x))² · sec²(x) + 5 · 4(csc(x))³ · -csc(x)cot(x)
  • Multiply: 6(tan(x))²sec²(x) - 20(csc(x))³csc(x)cot(x)
  • Simplify: 6tan²(x)sec²(x) - 20csc⁴(x)cot(x)
  • Factor: 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]

3 0
4 years ago
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