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KATRIN_1 [288]
4 years ago
13

There are ten fish in a pool. 2 die 8 of them drowned. How many are left?

Mathematics
2 answers:
sveta [45]4 years ago
3 0

Answer:

There are 10 alive,  and it depends on what the question meant by "How many of them are left?", because they all might be still in the bowl.

Step-by-step explanation:

posledela4 years ago
3 0

The Answer is 0 Because 10-2 = 8 and 10-8= 2 so if we add 2+8= 10

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Given the quadratic function f(x) = (x + 6)(x – 3):
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

Given quadratic function is,

f(x) = (x + 6)(x - 3)

For x-intercept,

Substitute the value f(x) = 0.

(x + 6)(x - 3 = 0

x = 3, -6

So the x-intercepts will be,

(-6, 0) and (3, 0)

For y-intercept,

Substitute the value for x = 0,

f(0) = (0 + 6)(0 - 3)

     = -18

Therefore, y-intercept of the given quadratic function will be (0, -18).

4 0
3 years ago
Simplify please help me with this question
tankabanditka [31]

Answer:

a^4

<h3>Explanation:</h3>

a^2×a^3= a^5(a^2+3)

a^5/a= a^4(a^5-1)

5 0
2 years ago
Find the z-score such that the area under the standard normal curve to the left is 0.79.
Varvara68 [4.7K]

Answer:

1

Step-by-step explanation:

hope this helps

8 0
4 years ago
If x is an integer, then is -x positive?
Andrei [34K]

Answer:

If x is an integer, then for values of x ≤ 0 would -x be positive.

General Formulas and Concepts:

<u>Math</u>

  • Integers

Step-by-step explanation:

We know that integers comprise of the number line from -∞ to ∞. We can have numbers like -3, -2, -1, 0, 1, 2 ,3.

If we say that x is an integer, and that -x must be positive, then that means the integer x must be negative, because a negative times a negative is a positive.

∴ x can only be negative integers, thus giving us x ≤ 0.

3 0
3 years ago
A rock outcrop was found to have 95.82% of its parent U- 238 isotope remaining. Approximate the age of the outcrop. The half-lif
mixer [17]

Answer:

A) 277 million years

Step-by-step explanation:

Here, decay of U-238 is first order reaction. (since most of the nuclear decays are first order).

so, the equation t = \frac{1}{k} × ln(\frac{A(0)}{A})

where, t = time from start of reaction

           k = reaction constant

           A(0) = initial concentration; A = present concentration.

     ⇒ 4.5 billion = 4500 million years = \frac{1}{k}× ln2.

Now, given 95.82% of parent U-238 isotope is left.

⇒ t = \frac{1}{k} × ln(\frac{A(0)}{A})

  t = \frac{4500}{ln2} × ln(\frac{100}{95.82})

⇒ t ≅ 277 million years.

5 0
3 years ago
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