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DanielleElmas [232]
3 years ago
13

3 expressions that are equivalent to 9^4

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

Step-by-step explanation:

hello :

9^4 = (3^2)^4

9^4 =3^8

9^4 =(3^4)^2 = 81^2

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The coordinates of the endpoints of and are A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4). Which condition proves that ?
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For two line segments to be parallel, their slopes must be equal.

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<span> (y4-y3)/(x4-x3)=(y2-y1)/(x2-x1)</span>
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If it’s costs 60 cents for 125 grammes. How much would 100 grammes cost?
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➷ Work out the cost per gram

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3 years ago
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Jaila went to the butcher and bought 2.42 pounds of ground beef, ¾ pound of bacon, and 3 pork chops that each weigh .36 of a pou
kirill [66]

Answer: 4.25 pound of meat

Step-by-step explanation:

This is a addition questions, all you have to do is to add the numbers together. But you have to convert all the fractions and decimal to the same thing first. In this case, I'll convert all the fraction to decimal.

2.42 + 0.75 + 0.36  ✕ 3 = 4.25 pound

7 0
2 years ago
Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
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\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6

6 0
3 years ago
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