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Kamila [148]
3 years ago
5

3rd multiple of 8 plz help me​

Mathematics
2 answers:
aalyn [17]3 years ago
8 0

Answer:

78 and the rest are all the same time u need to tell me pls I am not going to be able to make money on the menu and I will call you to make sure you are you and I will call you when I get the chance and I will call you when I get back from work and I will call you when I get the chance

Mariana [72]3 years ago
5 0

Answer:

2

Step-by-step explanation:

Its simple.

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Answer:Wanna play warzone?

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7 0
3 years ago
Eleven books are stacked on top of each other. If each book is 2.35cm thick, find the height of the stack
dangina [55]

Answer:

It's height is 2.35 * 11 = 25.85 cm

Hope it helps..

3 0
3 years ago
Carlos has a box of coins that he uses when playing poker
Fofino [41]

Answer:

so far i got 8 quarters 14 dimes and 13 pennies

Step-by-step explanation:

ill update you if i got any closer

6 0
3 years ago
two planes, which are 1965 miles apart, fly toward each other. their speeds differ by 55mph. if they pass each other other in 3
Alexus [3.1K]

The speed of the planes are 300 miles per hour and 355 miles per hour.

<u>Solution:</u>

Given, Two planes are 1965 miles apart, flying toward each other.  

Their speeds differ by 55 mph.  

They pass each other in 3 hours,  

We have to find what is the speed of each?

Let the speed of 1st plane be s miles per hour, then speed of the other plane will be s + 55 miles per hour.

And, distance travelled by 1st plane be d, then distance travelled by other plane will be 1965 – d miles

Now, we know that, distance = speed \times time

So, for 1st plane ⇒ \mathrm{d}=\mathrm{s} \times 3

For 2nd plane ⇒ 1965-d=(s+55) \times 3

By using 1st plane equation

1965 – 3s = 3s + 165  

1965 – 165 = 3s + 3s

6s = 1800

s = 300

So, speed of 1st plane is 300 miles per hour, then speed of 2nd plane  will  be 300 + 55 = 355 miles per hour.

Hence, the speed of the planes are 300 miles per hour and 355 miles per hour.

4 0
4 years ago
Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on
Goryan [66]

Answer:

\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=> a=\dfrac{276}{4}=69

And then from (1) b = 80 - 69 = 11

Hope this helps

4 0
3 years ago
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