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3 years ago

10

-3/8+5/9 jk cmmmmnvvvvvvv.Vzjnvjks.Fjnv.Fkjnxfvvvvvvvvvvvvvvvvvvvvvvvvv.....

1 answer:

Viefleur [7K]3 years ago

4 0

Answer:

0.1805

Step-by-step explanation:

Hopefully you know how to use a calculator for this

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3 years ago

suppose that you have 3000$ to invest. which investment yields the greater return over a 10 year period: 8.04% compounded daily

Ksenya-84 [330]

Answer: Option A: 8.04% compounded daily

<u>Step-by-step explanation:</u>

$A = P\bigg(1+\dfrac{r}{n}\bigg)^{nt}\qquad where\\\\\bullet A = \text{accrued amount (principal plus interest earned)}\\\bullet P = \text{principal (amount invested)}\\\bullet r = \text{rate (in decimal form)}\\\bullet n=\text{number of times compounded in one year}\\\bullet t=\text{time (number of years)}\\\\\\Option\ A:\\A = \text{unknown}\\P=3000\\r=8.04\%\rightarrow 0.0804\\n=\text{daily}\rightarrow 365\\t=10\\\\A=3000\bigg(1+\dfrac{0.0804}{365}\bigg)^{365\times 10}\\\\.\ =\$ 6,702.79$

$Option\ B:\\A = \text{unknown}\\P=3000\\r=8.1\%\rightarrow 0.081\\n=\text{quarterly}\rightarrow 4\\t=10\\\\A=3000\bigg(1+\dfrac{0.081}{4}\bigg)^{4\times 10}\\\\.\ =\$ 6,689.37$

Option A results in the greater amount of money.

7 0

4 years ago

Solve for x.<br><br> (x−2)^2+2=38<br><br> x= ___ or x= ___

Elan Coil [88]

Answer:

$x \: = \: \boxed{ \bold{ - 4 }}\: \: \text{or} \: \: x \: = \: \boxed{ \bold{ 8}}$

Step-by-step explanation:

$(x \: - \: 2 {)}^{2} \: + \: 2 \: = \: 38$

${x}^{2} \: - \: 4x \: + \: 4 \: + \: 2 \: = \: 38$

${x}^{2} \: - \: 4x \: + \: 6 \: = \: 38$

${x}^{2} \: - \: 4x \: + \: 6 \: - \: 38 \: = \: 0$

${x}^{2} \: + \: 4x \: - \: 8x \: - \: 32 \: = \: 0$

$x \: \times \: (x \: + \: 4) \: - \: 8(x \: + \: 4) \: = \: 0$

$(x \: + \: 4) \: \times \: (x \: - \: 8) \: = \: 0$

When it happens that the product of the factors is the same as zero. It is divided into two possible cases.

$x \: + \: 4 \: = \: 0 \\ x \: - \: 8 \: = \: 0$

We solve the two equations:

$x \: = \: - 4 \\ x \: = \: 8$

<h2>Answer: </h2>

$x \: = \: - 4 \\ x \: = \: 8$

<h3><em><u>MissSpanish</u></em></h3>

6 0

2 years ago