Please Help! Its calculus but it is also 30 points!!!
1 answer:
To solve this, we are going to be revolving this area around the line x=7, which means that we are rotating with respect to y, meaning we must change the equations to x= f(y).
Now that we have those two equations, we can graph this (I'm going to assume this is a calculator FRQ/MC problem) and find our top and bottom bounds. Looking at the graph, we can see that the bounds are 0 and 2. Now comes the part in which we set up the equation of the integral.
Because this area is being revolved around the line x=7, we can set up an equation with this in mind. We use y-7 in order to take into account the axis of rotation, and the equation of the line x=y, and the same with the other function. We put y-7 first because it is the outer function in relation to the function y=.5x^2. Now we integrate (and once again, assuming that this is a calculator FRQ/MC) and get 25.1327.
Please, please, please let me know if this is incorrect, because I'm a bit hazy on this as well, I'll make sure to correct it as soon as possible. Thanks.
Now that we have those two equations, we can graph this (I'm going to assume this is a calculator FRQ/MC problem) and find our top and bottom bounds. Looking at the graph, we can see that the bounds are 0 and 2. Now comes the part in which we set up the equation of the integral.
Because this area is being revolved around the line x=7, we can set up an equation with this in mind. We use y-7 in order to take into account the axis of rotation, and the equation of the line x=y, and the same with the other function. We put y-7 first because it is the outer function in relation to the function y=.5x^2. Now we integrate (and once again, assuming that this is a calculator FRQ/MC) and get 25.1327.
Please, please, please let me know if this is incorrect, because I'm a bit hazy on this as well, I'll make sure to correct it as soon as possible. Thanks.
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Answer:
A. From the information given in the graph, we have;
The grain yield in pounds per acre for Europe in 1960 is approximately 1,600 Pounds per Acre
The grain yield in pounds per acre for Europe in 2015 is approximately 5,100 Pounds per Acre
The rate of change of grain yield in Europe ≈ (5,100 - 1,600)/(2015 - 1960) = 63. Pounds per Acre per year
The grain yield in pounds per acre for Sub-Saharan Africa in 1960 is approximately 800 Pounds per Acre
The grain yield in pounds per for Sub-Saharan Africa 2015 is approximately 1,250 Pounds per Acre
The rate of change in grain yield in Sub-Saharan Africa ≈ (1,250 - 800)/(2015 - 1960) = 8. Pounds per Acre per year
Therefore, the grain yield per acre per year in Europe is increasing approximately 8 times the increase in Sub-Saharan Africa
B. Given that the rate of increase in the pounds of grain per Acre per year in Europe is progressively increasing above the average rate of world rate, the market for the grains produced in Europe will be partly the developing countries, thereby reducing the number of farms found in developing countries
C. In stage 4 demographic transition the population growth is stabilizing and therefore where there is an increase in grain yields, there will be an increase in farming and economic activity and a reduction in population growth
Where there is a decrease in grain yield, there will be an increase in activities to restore supply and therefore, a reduction in population
D. One limitation of the data in describing food security at a regional scale is the information required on the population figures in a given region involved in grain farming
Explanation: