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Bingel [31]
4 years ago
11

Missing side length

Mathematics
1 answer:
ratelena [41]4 years ago
6 0

Answer:

Since ΔABC ~ ΔQRS, we know that:

=> AB/QR = BC/RS

=> 2/n = 6/15

=> n = (2 × 15)/6 = 5

*You can also use AB/QR = AC/ QS to calculate n

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Step-by-step explanation:

6 0
3 years ago
Slove for the variable 2(y - 5) = 5y + 23
olasank [31]

Answer:

y = -11

Step-by-step explanation:

8 0
3 years ago
Find the shaded angle
masya89 [10]

Answer:

332°

Step-by-step explanation:

Given is an isosceles triangle,

Measures of base angles of an isosceles triangle are equal.

Therefore,

Measure of central angle

= 180° - ( 76° + 76°)

= 180° - 152°

= 28°

Measure of shaded angle

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5 0
3 years ago
What are the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of
Mrrafil [7]

Answer:

\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )

Step-by-step explanation:

Given: P is Three-fifths the length of the line segment from K to J

To find: x- and y-coordinates of point P on the directed line segment from K to J

Solution:

Section formula:

Let point K and J be (x_1,y_1)\,,\,(x_2,y_2) such that the point p(x,y) divides KJ in ratio m:n

Then coordinates of point  P are given by \left ( \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n} \right )

Take m:n=3:5

So,

coordinates of point P = \left ( \frac{3x_2+5x_1}{3+5},\frac{3y_2+5y_1}{3+5} \right )=\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )

7 0
4 years ago
How do I solve for n? 13=n-8
choli [55]
N in (-oo:+oo)

-13 = n-8 // - n-8

8-n-13 = 0

-n-5 = 0 // + 5

-n = 5 // * -1

n = -5

n = -5
3 0
3 years ago
Read 2 more answers
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