It was a sunny afternoon<u> </u><em><u>in late October</u></em><em> </em>(prep=adv). Muriel and I had decided to check properties for sale in the countryside. We had always enjoyed toying with the idea of<em> </em><em><u>finding</u></em><u> </u><u>(np)</u> the perfect place<u> </u><u><em>to live </em></u><em>(</em>inf=adj). So we got into the car <u><em>to start as soon as possible</em></u><u> </u>(inf=adv). <u><em>After driving</em></u> (part) for hours we reached the spot, a stretch of fields forgotten <u><em>in the middle of nowhere. </em></u>(prep=adj). We had been told about this lonely place by my uncle Bob<em>, </em><u><em>the hermit</em></u><em> </em>(app).<u><em>To be </em></u><em>standing there in the absolute silence </em>(inf=n) of the place was unnerving. <em>We could hear the blades of grass rustling against each other and smell the strong stench of cows grazing nearby.</em> (compound)<em>Never had we been away from the city or felt the isolation of a rural area for this reason we rushed back to the car and drove back to our apartment as fast as we could.</em> (compound-complex).
<em>Answer:</em>
<em>¿Qué pasa con eso, necesitará ayuda o? como a que hora porque estoy disponible 4-8 de la tarde</em>
Verbal irony, situational irony, dramatic irony?
Find the moles of Boron and of Chlorine:
Assume there are 100 g of the compound in all
Boron: 9.224% --> .09224 (convert percent to decimals)
.09224*100g = 9.224g Boron (theoretical amt)
9.224g* 1mol/10.81g (molar mass Boron) = .8533 moles Boron
