To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -8 ± √((8)^2 - 4(2)(3)) ] / ( 2(2) )
x = [-8 ± √(64 - (24) ) ] / ( 4 )
x = [-8 ± √(40) ] / ( 4)
x = [-8 ± 2*sqrt(10) ] / ( 4 )
x = -2 ± sqrt(10)/2
The answers are -2 + sqrt(10)/2 and -2 - sqrt(10)/2.
Answer:
The diameter of the circle is 40 units
Step-by-step explanation:
Answer:
4.8 × 10-5
Step-by-step explanation:
I think it’s -3 because I’m guessing you have to times the 4x with the number inside the parenthesis so it would be 4x-12x = 23 and 4-12 is -8 = 23 and 23 divided by -8 is -3
Answer: P(B|G) = 3/5 = 0.6
the probability that the guest is the friend of bride, P(bride | groom) is 0.6
Complete Question:
The usher at a wedding asked each of the 80 guests whether they werea friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Given that the randomly chosen guest is the friend of groom, what is the probability that the guest is the friend of bride, P (bride | groom)
Step-by-step explanation:
The conditional probability P(B|G), which is the probability that a guest selected at random who is a friend of the groom is a friend of the bride can be written as;
P(B|G) = P(B∩G)/P(G)
P(G) the probability that a guest selected at random is a friend of the groom.
P(G) = number of groom's friends/total number of guests sample
P(G) = 50/80
P(B∩G) = the probability that a guest selected at random is a friend is a friend of both the bride and the groom.
P(B∩G) = number of guests that are friends of both/total number of sample guest
P(B∩G) = 30/80
Therefore,
P(B|G) = (30/80)/(50/80) = 30/50
P(B|G) = 3/5 = 0.6