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4 years ago

PLEASE HELP ME WITH THIS !!

Mathematics

2 answers:

Vikentia [17]4 years ago

7 0

The answer is number 1 since a function can't have x repeated. all the other ones have a single x giving 2 numbers. if this happens once it is no longer a function.

Lena [83]4 years ago

3 0

the top one, use the vertical line test and if their are more than two points on the vertical line when testing the points then the relation is not a function. Which tells you that the last three are not a function.

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ArbitrLikvidat [17]

Answer:

13 i got it right on khan

Step-by-step explanation:

8 0

3 years ago

F (x)=2x+1 and g (x)=x^2-7, find (f/g)(x)

Andrej [43]

(f/g)(x) just means f(x)/g(x)

So the answer is (2x+1)/(x^2-7)

5 0

3 years ago

Read 2 more answers

HELP PLEASE

kolezko [41]

Answer: 16 feet is the width and 25 is length

Step-by-step explanation:

x*(2x-7)=400

Word problem written in numerical form^^^^

Solve for x to get 16

length = 2(16)-7= 25

Check our work

16*25=400 yay

6 0

3 years ago

Determine if the following conclusion is valid. Why or why not?

ludmilkaskok [199]

Answer:

The first option

Step-by-step explanation:

It is biased as her friends are all more likely to go considering how involved she is with it.

4 0

3 years ago

38.2834. V1435. 36- 5637. v40. V4141. 214265 43. 12 445 8 -3ja 47. V3248. V4749. V99 50

aliya0001 [1]

No, your answer are wrong (I assume that the question asks to simplify the roots). You can only remove (their square is placed in from of the root and multiplied by it) the numbers from the root that are squares, the lest must stay, like this:

$\sqrt{14} = \sqrt{2*7} ,$ no roots are among the factors, nothing can be removed
$\sqrt{14} = \sqrt{2*7} ,$ nothing can be removed
$-\sqrt{39} = -\sqrt{3*13}$ nothing can be removed
$-\sqrt{56} = -\sqrt{2*2*2*7}=-2\sqrt{14} ,$
$-\sqrt{77} = -\sqrt{11*7} ,$ nothing can be removed
$\sqrt{41} = \sqrt{41} ,$ nothing can be removed
$\sqrt{21} = \sqrt{3*7} ,$ nothing can be removed
$- \sqrt{65} = -\sqrt{5*13} ,$ nothing can be removed
$-\sqrt{12} = -\sqrt{2*3*4} =-2\sqrt{4},$
$\sqrt{13} = \sqrt{13} ,$ nothing can be removed
$\sqrt{32} = \sqrt{4*4*2} =4\sqrt{2},$
$\sqrt{47} = \sqrt{47} ,$ (47 is prime) nothing can be removed
$-\sqrt{99} = -\sqrt{9*11}= -3\sqrt{11} ,$

4 0

3 years ago