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SCORPION-xisa [38]
3 years ago
10

The pound has three kinds of dogs: pit bull, chihuahuas and mutts. All but 23 of the dogs are pit bull, all but 17 are chihuahua

s, and all but 28 of the dogs are mutts. How may dogs are in the pound?
Mathematics
1 answer:
Georgia [21]3 years ago
5 0

Answer:

There are 68 dogs in the pound.

Step-by-step explanation:

Number of pit bull dogs in a pound = P = 23

Number of chihuahuas dogs in a pound = C = 17

Number of mutts dogs in a pound = M = 28

Total number of dogs in a pound = T

T = P+C+M=23+17+28=68

There are 68 dogs in the pound.

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3 years ago
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The hexadecimal number is 0xFEE. what will be the octal number of this?
Vikentia [17]

Answer:

0xFEE₁₆ = 7756₈

Step-by-step explanation:

Convert the hexadecimal number to decimal first

0xFEE

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F = 15

Then convert them to binary

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Remainder = 1

0           F      E       E

0000  1111 1110  1110

Take groups of three

and multiply with 2^n where n is the place of the digit

111          111   101   110

4,2,1     4,2,1    4,2,1  4,2,1

4+2+1  4+2+1  4+0+1  4+2+0

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8 0
3 years ago
6(22+9) what is this answer
scoundrel [369]
If you would like to solve 6 * (22 + 9), you can calculate this using the following steps:

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3 years ago
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Step-by-step explanation:

Use a calculator

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nika2105 [10]

0.6/10^-2

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8 0
3 years ago
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