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SCORPION-xisa [38]
3 years ago
10

The pound has three kinds of dogs: pit bull, chihuahuas and mutts. All but 23 of the dogs are pit bull, all but 17 are chihuahua

s, and all but 28 of the dogs are mutts. How may dogs are in the pound?
Mathematics
1 answer:
Georgia [21]3 years ago
5 0

Answer:

There are 68 dogs in the pound.

Step-by-step explanation:

Number of pit bull dogs in a pound = P = 23

Number of chihuahuas dogs in a pound = C = 17

Number of mutts dogs in a pound = M = 28

Total number of dogs in a pound = T

T = P+C+M=23+17+28=68

There are 68 dogs in the pound.

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What equation describes the circle that is centered at (8, 3) and has a radius of 9
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Answer:

<h3> (x-8)²+(y-3)² = 81</h3>

Step-by-step explanation:

The general equation of a circle is expressed as;

(x-a)²+(y-b)² = r² where;

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(x-a)²+(y-b)² = r²

(x-8)²+(y-3)² = 9²

(x-8)²+(y-3)² = 81

hence the required equation is  (x-8)²+(y-3)² = 81

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3 years ago
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A1<br> B2<br> C3<br> D4<br> what is it
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Lee is staying at a hotel. The cost of the first night is $240. The cost for each night after that is $210. Let y represent the
GenaCL600 [577]

A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.

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F(x)= 240 +210x.

Learn more about Sequence:

brainly.com/question/12246947

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