Answer:
38%
Step-by-step explanation:
Given that X,the hours per week the music student practice follow a normal distribution.
X:N(8,4)
We have to find the percentage of students who practice between 6 and 10 hours.
6<x<10 implies converting to z
We know z = (x-mean)/sigma = (x-8)/4
Hence 6<x<10 is equivalent to (6-8/4)<Z<(10-8/4)
= |z|<0.5
From std normal table we find this area equals = 0.1915+0.1915
=0.3830 = 0.38 (rounded off)
Hence required percentage = 0.38x100 = 38%
Answer:
Step-by-step explanation:
This is the SUM of two PRODUCTS.
12p + 7 > 139
subtract 7 from both sides
12 p > 132
divide both sides by 12
p > 11
30/18 = 5/3 = 1 2/3 as a mixed number.
