Answer:
40
Step-by-step explanation:
We can see that at 1 minute there is 40 beats, at 2 minutes there is 80 beats, at 3 minutes there is 120 beats, at 4 minutes there is 160 beats and at 5 minutes there is 200 beats. If we divide each of the beats by its corresponding minute we will get 40
40 beats at 1 minute → 40 ÷ 1 = 40
80 beats at 2 minutes → 80 ÷ 2 = 40
120 beats at 3 minutes → 120 ÷ 3 = 40
160 beats at 4 minutes → 160 ÷ 4 = 40
200 beats at 5 minutes → 200 ÷ 5 = 40
You can use the quadratic formula with it which will be easier
or simple factoring
it will be (5x-11)(7x+4)
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!