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alex41 [277]
3 years ago
10

Find the volume of a rectangular prism with a base that has an area of 22 square centimeter and a height of 8 centimeters.

Mathematics
1 answer:
Jlenok [28]3 years ago
3 0

Answer:

176cm³

Step-by-step explanation:

Multiply area of base times height

22cm² × 8cm = 176cm³

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3 years ago
Find the volume of the cone. Round your answer to the nearest tenth.
Roman55 [17]

Answer:

<u>65.4 cubic inches</u>

Step-by-step explanation:

Formula for the volume of a cone :

<u><em>Volume (cone) = 1/3πr²h</em></u>

<u><em /></u>

=============================================================

Given :

⇒ diameter = 5 in. → radius = <u>2.5 in.</u>

⇒ height = <u>10 in.</u>

<u />

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Solving :

⇒ Volume (cone) = 1/3 × π × (2.5)² × 10

⇒ Volume (cone) = 62.5π/3

⇒ Volume (cone) = <u>65.4 cubic inches</u>

8 0
1 year ago
Can anyone help with this question
WARRIOR [948]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
in this line of circles, the ratio of the red circles to blue circles is 1:3. how many more red circles would need to be added t
Tems11 [23]

Answer:

Step-by-step explanation:

If we assume that initially

Number of red counter is 1

Number of blue counter is 3

Now to make ratio reverse you need to add 8 more red counters so that ratio becomes

9:3=3:1

5 0
3 years ago
Polly's Polls asked 1850 second-year college students if they still had their original major. According to the colleges, 65% of
suter [353]

Answer:

The probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424

Step-by-step explanation:

The variable that assigns the value 1 if a person had its original major and 0 otherwise is a Bernoulli variable with paramenter 0.65. Since she asked the question to 1850 people, then the number of students that will have their original major is a Binomial random variable with parameters n = 1850, p = 0.65.

Since the sample is large enough, we can use the Central Limit Theorem to approximate that random variable to a Normal random variable, which we will denote X.

The parameters of X are determined with the mean and standard deviation of the Binomal that we are approximating. The mean is np = 1850*0.65 = 1202.5, and the standard deviation is √np(1-p) = √(1202.5*0.35) = 20.5152.

We want to know the probability that X is between 0.64*1850 = 1184 and 0.66*1850 = 1221 (that is, the percentage is between 64 and 66). In order to calculate this, we standarize X so that we can work with a standard normal random variable W ≈ N(0,1). The standarization is obtained by substracting the mean from X and dividing the result by the standard deviation, in other words

W = \frac{X-\lambda}{\sigma} = \frac{X-1202.5}{20.5152}

The values of the cummulative function of the standard normal variable W, which we will denote \phi are tabulated and they can be found in the attached file.

Now, we are ready to compute the probability that X is between 1184 and 1221. Remember that, since the standard random variable is symmetric through 0, then \phi(-z) = 1-\phi(z) for each positive value z.

P(1184 < X < 1221) = P(\frac{1184-1202.5}{20.5152} < \frac{X-1202.5}{20.5152} < \frac{1221-1202.5}{20.5152})\\ = P(-0.9018 < W < 0.9018) = \phi(0.9018) - \phi(-0.9018) = \phi(0.9018)-(1-\phi(0.9018))\\ = 2\phi(0.9018)-1 = 2*0.8212-1 = 0.6424

Therefore, the probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424.

Download pdf
4 0
3 years ago
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