Question

Suppose a computer technical support representative can answer calls from 8 customers in an hour. What is the probability that a customer will be on hold less than 15 minutes?

Answer 1

Answer:

D edge

Step-by-step explanation:

Answer 2

Answer:

Option d

Step-by-step explanation:

We need 2 fundamental data to solve this problem.

1.- Average number of clients attended in 1 hour.

2.- Time in which it is expected that a client will be attended.

They tell us that the average number of clients served in an hour is m = 8

They tell us to calculate the probability that the client will be seen in less than 15 minutes.

But the time t in the formula is given in hours.

Therefore we must write 15 minutes according to hours.

We know that $1\ hour = 60 minutes$.

So:

$15\ minutes[\frac{1\ hour}{60\ minutes}] = 0.25\ hours$.

Now we substitute in the formula $m = 8$ and $t = 0.25$ to find P.

$P = 1 -e^{-mt}\\\\P = 1- e^{-(8)(0.25)}\\\\P = 1 - e^{-2}\\\\P = 0.8646\\\\P= 86\%$