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umka2103 [35]
3 years ago
14

Suppose a computer technical support representative can answer calls from 8 customers in an hour. What is the probability that a

customer will be on hold less than 15 minutes?

Mathematics
2 answers:
Paraphin [41]3 years ago
6 0

Answer:

D edge

Step-by-step explanation:

Ganezh [65]3 years ago
4 0

Answer:

Option d

Step-by-step explanation:

We need 2 fundamental data to solve this problem.

1.- Average number of clients attended in 1 hour.

2.- Time in which it is expected that a client will be attended.

They tell us that the average number of clients served in an hour is m = 8

They tell us to calculate the probability that the client will be seen in less than 15 minutes.

But the time t in the formula is given in hours.

Therefore we must write 15 minutes according to hours.

We know that 1\ hour = 60 minutes.

So:

15\ minutes[\frac{1\ hour}{60\ minutes}] = 0.25\ hours.

Now we substitute in the formula m = 8 and t = 0.25 to find P.

P = 1 -e^{-mt}\\\\P = 1- e^{-(8)(0.25)}\\\\P = 1 - e^{-2}\\\\P = 0.8646\\\\P= 86\%

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Answer:

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