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blagie [28]
3 years ago
8

suppose that 16% of teenagers who play video gmes would enjoy playing a new super mario game the manufacturer doesnt know this a

ctual proportion and plans on sampling a random sample of 80 teenage game players ap stats a. Calculate the standard deviation of the sampling distribution of p. b. Are the conditions for inference met?Explain c. If a different sample size would result in the standard deviation of the sample distripution of p= 0.037, is the sample size smaller or larger than 80?Explain
Advanced Placement (AP)
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:Accordingly, the Necessary Sample Size is calculated as follows:

Necessary Sample Size = (Z-score)² * StdDev*(1-StdDev) / (margin of error)²

For example, given a 95% confidence level, 0.5 standard deviation, and a margin of error (confidence interval) of +/- 5%. Necessary Sample Size =

((1.96)² x 0.5(0.5)) / (0.05)²

(3.8416 x 0.25) / .0025

0.9604 / 0.0025

384.16

So in order to get 95% confidence level, with confidence interval of +/- 5%, and standard deviation of 0.5, I have to survey 385 samples.

As I  usually calculate the average value on 100 samples. So what is the confidence level I can get?

Is anyone who has experience on this can share something.

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3 years ago
The diagram shows the length and width of a cell phone, and the length of a larger
Volgvan

Answer:

The width of the bigger phone is 2.99 in

Explanation:

Given

W_1 = 2.6in

L_1 = 5.4in

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See attachment for the measure of cell phones

Required

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To do this, we make use of the following equivalent ratios.

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This gives:

5.4\ in : 2.6\ in  : 6.21\ in : W_2

Express as fractions

\frac{5.4\ in}{2.6\ in} = \frac{6.21\ in}{W_2}

\frac{5.4}{2.6} = \frac{6.21\ in}{W_2}

Make W2 the subject

W_2 = \frac{6.21 * 2.6\ in}{5.4}

W_2 = \frac{16.146\ in}{5.4}

W_2 = 2.99\ in

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3 years ago
Which class of fire extinguisher is appropriate for a fire involving a flammable liquid?
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4 0
4 years ago
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This is the complete text in Spanish:

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<u>Reflexive verbs</u>

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