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noname [10]
3 years ago
15

Can someone explain this document to me, I don't understand it.

Advanced Placement (AP)
1 answer:
BlackZzzverrR [31]3 years ago
6 0

I think the document is explaining who Luzia is and what she did. People (including herself) believed that God was working through her and gave her the power to cure people throughout Rio de Janeiro. The document was the captain's testimony as to what he saw her do and what he heard of her in her Inquisition trial.

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A shift to the right in the Aggregate Demand indicates what has occurred?
barxatty [35]

Answer:

Option D

Explanation:

If Aggregate Demand happens to shift to the right that means the "consumer spending has increased" or option D. In this type of demand when it shifts to the right that means the buyer wants more of it and the demand for it increases while if the Aggregate demand shifts to the left that means they'res a decrease in demand for your product.

Hope this helps.

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3 years ago
In one paragraph, describe how you might use elaboration to remember a piece of important information.
mote1985 [20]
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6 0
3 years ago
I can’t figure this problem out
Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

\int\limits^4_1 {(3f(x)+2)} \, dx

So lets break this up into two different integrals that represent the same area.

\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

\int\limits^4_1 {f(x)} \, dx

But since we have these values we can say that:

-3 - 2 = -5

Which means that \int\limits^4_1 {f(x)} \, dx = -5

So now we can evaluate \int\limits^4_1 {(3f(x)+2)} \, dx

Lets first break up our integrand into two integrals

\int\limits^4_1 {(3f(x)+2)} \, dx = 3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx

Now we can evaluate this:

We know that \int\limits^4_1 {f(x)} \, dx = -5

So:

3(-5)+2[x] where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

5 0
3 years ago
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