What is the zero of the quadratic polynomial 4s2– 4s + 1 ???
2 answers:
Answer:
s = 1/2
Step-by-step explanation:
Solve for s:
4 s^2 - 4 s + 1 = 0
Divide both sides by 4:
s^2 - s + 1/4 = 0
Write the left hand side as a square:
(s - 1/2)^2 = 0
Take the square root of both sides:
s - 1/2 = 0
Add 1/2 to both sides:
Answer: s = 1/2
Answer:
s =
Step-by-step explanation:
To find the zero set the quadratic equal to zero, that is
4s² - 4s + 1 = 0 ← in standard form
(2s - 1)(2s- 1) = 0 ← in factored form
(2s - 1)² = 0 ← perfect square, thus
2s - 1 = 0 ⇒ 2s = 1 ⇒ s = ← is the zero
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
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