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Alex73 [517]
3 years ago
8

5 7/12 less than or greater than

Mathematics
1 answer:
Andreyy893 years ago
5 0
Less than or greater than what?
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pam cuts 75 inches of ribbon into 6 equally sized pieces with no ribbon left over whats the length in inches of each piece of ri
Elden [556K]

Answer:

12.5 inches? I think

Step-by-step explanation:

gotta go do my work

5 0
3 years ago
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Integration of the following function
DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}

d\bar{c}=\left (  -6x^{-2}+\frac{1}{6}\right )dx

Now, integrating both sides

\int d\bar{c}=\int \left (  -6x^{-2}+\frac{1}{6}\right )dx

\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1

\bar{c}=6x^{-1}+\frac{1}{6}x+k_1

6 0
3 years ago
Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin
ozzi

I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta  \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt

by using the integration formula

we get,

\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c

now put the value of t=\sin\theta in the above equation

we get,

\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c

hence proved

7 0
2 years ago
The scale model of a rectangular garden is 1.5 ft by 4 ft. The scale model is enlarged by a scale factor of 7 to create the actu
KengaRu [80]
I will say 42, I am sorry if I am incorrect.
4 0
2 years ago
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What is the quadratic regression equation that fits these data?
elena55 [62]

9514 1404 393

Answer:

  D.  y = -0.32x² -1.26x +15.81

Step-by-step explanation:

This is one of those multiple-choice questions where you only need a vague idea of what the answer is supposed to look like.

In this case the answer must be a quadratic equation with a negative leading coefficient. (The parabola opens downward.)

The only answer choice that is a 2nd degree polynomial with a negative leading coefficient is choice D.

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A: linear equation

B: exponential equation

C: quadratic that opens upward (positive leading coefficient)

D: quadratic that opens downward -- the answer you're looking for

4 0
2 years ago
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