Answer:
Explanation:
Given: that,
Angle of inclination of the surface,
mass of the crate,
Force applied along the surface,
distance the crate moves after the application of force,
a) work done = F× s
work done = 230 × 1.1
work done = 253 J
b) Work done by the gravitational force:
where:
g = acceleration due to gravity
h = the vertically downward displacement
Now, we find the height:
So, the work done by the gravity:
∵direction of force and displacement are opposite.
= - 343.54J
c)
The normal reaction force on the crate by the inclined surface:
d)
Total work done on crate is with respect to the worker:
Answer:
V₀ₓ = 10.94 m/s
V₀y = 18.87 m/s
Explanation:
To find the launch velocity, we use 1st equation of motion.
Vf = Vi + at
where,
Vf = Final Velocity of Ball = Launch Speed = V₀ = ?
Vi = Initial Velocity = 0 m/s (Since ball was initially at rest)
a = acceleration = 376 m/s²
t = time = 0.058 s
Therefore,
V₀ = 0 m/s + (376 m/s²)(0.058 s)
V₀ = 21.81 m/s
Now, for x-component:
V₀ₓ = V₀ Cos θ
where,
V₀ₓ = x-component of launch velocity = ?
θ = Angle with horizontal = 59.9⁰
V₀ₓ = (21.81 m/s)(Cos 59.9°)
<u>V₀ₓ = 10.94 m/s</u>
<u></u>
for y-component:
V₀ₓ = V₀ Sin θ
where,
V₀y = y-component of launch velocity = ?
θ = Angle with horizontal = 59.9⁰
V₀y = (21.81 m/s)(Sin 59.9°)
<u>V₀y = 18.87 m/s</u>
<u></u>
It corrodes the copper by oxydation
Answer:
the first one, The object moving through air
Answer:
Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
Explanation: